Answer:
a) E = 1.47 × 10^5 N/C
b) south
Explanation:
The magnitude of an electric field can be defined mathematically as;
E = F/q ........1
Where,
E = magnitude of the electric field
F = electric force
q = charge on the proton
Given;
F = 2.36 × 10^-14 N
Note that charge on a proton is known as Qp = 1.602 × 10^-19 C
q = 1.602 × 10^-19 C
Substituting into equation 1, we have;
E = 2.36 × 10^-14 N/1.602 × 10^-19 C
E = 1.47 × 10^5 N/C
b) The direction of the electric field;
From equation 1
E = F/q ........1
since both electric field and electric force are vector quantity and q is a positive charge (constant), then both the electric field and electric force would be parallel to each other. Therefore the electric field is directed to the south also.
(When a vector is multiplied by a positive constant the direction remains the same)
Answer:
The answer is the 1st one
Answer:
an open system
Explanation:
which is contrasted with the concept of an isolated system which exchanges neither energy, matter, nor information with its environment.
Answer:
In order to walk across the floor, you push backwards on the floor with your foot. Newton's Third Law says that the reaction force to this action force is "floor pushes you forward" (Action: You push floor (backwards). Reaction: floor pushes you (forward).) So, when you walk, it is the floor that pushes you along!
Explanation:
.
Answer:
V = 308.06 miles/hour
θ = 13.13° west of north.
Explanation:
Airplane speed = V₁ = 300 miles/hour
Wind speed = V₂ = 70 miles/hour
Resultant speed of the plane = V = ?
As airplane is trying to fly straight North and wind is blowing toward the west. So the angle between airplane velocity and wind velocity is 90°.
By Pythagoras Theorem
V =
V =
V = 308.06 miles/hour
θ = tan⁻¹(70/300)
θ = 13.13° west of north.