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shtirl [24]
4 years ago
12

Which pair of properties apply to both sound and electromagnetic waves?

Physics
1 answer:
Basile [38]4 years ago
5 0
The properties would be energy and length
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an ice sheet 5m thick covers a lake that is 20m deep. at what is the temperature of the water at the bottom of the lake?
muminat

Answer:

4°C

Explanation:

Water is densest at 4°C.  Since dense water sinks, the bottom of the lake will be 4°C.

6 0
4 years ago
In the equation y =cnat2 you wish to determine theinteger value (1,2 etc.) of the exponent n. the dimensions ofy, a, and t are k
kvasek [131]

<u>NO.</u><u>  Since </u><u>"c"</u><u> has no dimensions, the value of its exponent </u><u>"n" </u><u>is irrelevant to dimensional analysis, and thus </u><u>dimension analysis </u><u>cannot be used to determine the value of </u><u>"n".</u>

Dimensional analysis is not applicable to proportionality constants, trigonometrical or exponential equations, equation consisting of sum or difference of some quantities and equation consisting of more than three fundamental quantities.

What is Dimensional analysis?

  • Dimensional Analysis is a problem-solving technique that makes use of the fact that any number or expression can be multiplied by one without changing its value.
  • It is also known as the Factor-Label Method or the Unit Factor Method. It is a practical method.

What is a dimensional analysis used for?

Dimensional analysis is a method used in engineering and the physical sciences to reduce physical properties like acceleration, viscosity, and energy to their three basic dimensions of length, mass, and time (T).

Learn more about Dimensional analysis

brainly.com/question/13078117

#SPJ4

5 0
2 years ago
if charge is located at center of spherical volume and electric flux through surface of sphere is Φ what would be flux through s
jonny [76]

Answer:

The flux will be nine times as great.

Explanation:

The electric flux due to a charge Q located in the center of a sphere can be obtained using Gauss's law. Considering a Gaussian surface in the form of a sphere of radius r:

\Phi_E=\int\limits {Ecos\theta dS} \,

The electric field (E) is parallel to the surface vector (dS), so \theta=0

\Phi_E=\int\limits{Ecos(0)dS} \,\\\Phi_E=E\int\limits{dS} \,\\\Phi_E=ES\\\Phi_E=E4\pi r^2

Since the electric flux is proportional to the square of the sphere's radius,  if radius of sphere were tripled, the flux will be nine times as great.

7 0
3 years ago
What are some issues that governments must consider before passing conservation policies? Check all that apply.
Otrada [13]

Answer: cost to implement conservation policies

environmental implications

benefit versus the cost

Explanation:

The conservation policies involves certain instructions which are required to be followed by the human society at all levels so as to conserve resources and protect them for future. The following are the issues which government should be consider before passing the conservation policies this includes:

1. cost to implement conservation policies : The procedure and expenditure for the implementation of the policies should be under control of the desired budget so that the plan can be efficiently executed.

2.environmental implications : The government should be concerned about the implication of the policies on the environment. For example the preservation of an endangered species in control condition from an ecosystem can disturb the overall balance of an ecosystem.

3.benefit versus the cost: The government should concern before expending on the implementation of the policies the benefits and costs of the desired policies.

7 0
3 years ago
Read 2 more answers
A helium balloon is filled to a volume of 2.88 x 103 L at 722 mm Hg and 19°C. When the balloon is released, it rises to an alti
inn [45]

Answer:

V₂=4.57 x 10³ L

Explanation:

Given that

V₁= 2.88 x 10³ L

P₁=722 mm  Hg

T₁ = 19°C

T₁ =292 K

P₂=339 mm Hg

T₂= - 55°C

T₂=218 K

Lets take final volume = V₂

We know that ideal gas equation

PV = m R T

By applying mass conservation

\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}

\dfrac{722\times 2.88\times 10^3}{292}=\dfrac{339\times V_2}{218}

V₂=4.57 x 10³ L

Therefore volume will be 4.57 x 10³ L

3 0
3 years ago
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