All categories

3 years ago

The circumference of a circle is 19.8mm. Find the length of the radius. Give your answer rounded to 1 DP.

1 answer:

3 0

Circumference of a circle = 2pie*r
= 19.8=2*314*r/100
= 1980 = 628*r
r = 1980/628
r = 3.13
~= 3 cm^2
Hope it helped!!!”!!!
Comment below

You might be interested in

Pick Two Points on the Line. Use "Rise over Run" to Find the Slope.<br> T<br> ✓

inn [45]

Answer:

Easiest to pick (0, 0) and (1, 1) probably, then slope is 1.

Step-by-step explanation:

Rise over run for (0, 0) and (1, 1) is rise up 1 and run over 1, so 1/1.

This means slope is 1

7 0

3 years ago

What is the full number of pie

IgorC [24]

The first 10 and 50 digits of Pi:
3.14159265 35897932384626433832795028841971693993751

4 0

3 years ago

Read 2 more answers

On the average, a grocer sells three of a certain article per week. How many of these should he have in stock so that the chance

olga2289 [7]

Answer:

Step-by-step explanation:

This is a Poisson distribution problem with the formula;

P(x;μ) = (e^(-μ)) × (μ^(x))/x!

We are told that the grocer sells three of a certain article per week. Thus;

μ = 3

Now, we want to find out How many of these should he have in stock so that the chance of his running out within a week is less than 0.01.

This means;

P(X > k) < 0.01

This can be rewritten as;

P(X ≤ k) < 0.99

Let's try x = 8

P(8;3) = (e^(-3)) × (3^(8))/8!

P(8;3) = 0.008

But; P(X ≤ 8) = 1 - 0.008 = 0.992

This is more than 0.99 and thus is not the answer

Let's try x = 7

P(7;3) = (e^(-3)) × (3^(7))/7!

P(7;3) = 0.022

But; P(X ≤ 7) = 1 - 0.022 = 0.978

Thus is less than 0.99.

Thus, stock should be 7

5 0

2 years ago

Which is the value of 10 x 5(2/5)x 4(1/3)?

Molodets [167]

Answer:

26 2/3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

How many of the first million positive integers share no common factors greater than 1 with 2020

Bingel [31]

9514 1404 393

Answer:

396,040

Step-by-step explanation:

Factors of 2020 are 2, 5, 101.

There are 1,000,000 / 1010 = 990 multiples of 2 and 5 and 101.

There are 1,000,000 / 505 -990 = 990 multiples of 5 and 101 only.

There are 1,000,000 / 202 -990 = 3,960 multiples of 2 and 101 only.

There are 1,000,000 / 10 - 990 = 99,010 multiples of 2 and 5 only.

There are 1,000,000 / 101 -990 -990 -3960 = 3,960 multiples of 101 only.

There are 1,000,000 / 5 -990 -990 -99,010 = 99,010 multiples of 5 only.

There are 1,000,000 / 2 -990 -3960 -99,010 = 396,040 multiples of 2 only.

So, the total number of multiples of any factor of 2020 is ...

990 +990 +3960 +99,010 +3960 +99010 +396040 = 603960

Then the number of integers in the first million that do not share any common factors greater than 1 with 2020 is ...

1,000,000 -603,960 = 396,040

4 0

3 years ago