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IRINA_888 [86]
4 years ago
14

..................................

Mathematics
1 answer:
Nina [5.8K]4 years ago
8 0
.....................hi.............
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On his first three tests, Shaun scored 88, 98, and 79. What score must he get on his fourth test to have an average (mean) of 80
solniwko [45]

Answer:

Step-by-step explanation:

let score in fourth test=x

88+98+79+x=80×4

265+x=320

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<h2>19.</h2><h3>Given</h3>
  • window width and height are in proportion to building width and height
  • window width and height are 11 in and 18 in, respectively
  • building height is 108 ft
<h3>Find</h3>
  • building width
<h3>Solution</h3>

The proportional relation can be written as

... (building width)/(building height) = (window width)/(window height)

Multiplying by (building height) gives

... (building width) = (building heigh) × (window width)/(window height)

... (building width) = 108 ft × (11 in)/(18 in)

... building width = 66 ft

<h2>21.</h2><h3>Given</h3>
  • map distance = 6.75 in
  • map scale = 1.5 in : 5 mi
<h3>Find</h3>
  • actual distance
<h3>Solution</h3>

The distances are in proportion, so

... (map distance) : (actual distance) = 1.5 in : 5 mi

Multiplying by (5 mi)/(1.5 in)×(actual distance), we have

... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi

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4 years ago
Create a direct variation equation. a b c or d​
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Step-by-step explanation:

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