The answer is the first option.. lets Start this correctly, we do this by doing distributive property, lets multiply x^2 times 3x and we will get 3x^3 that is our first digit and as we can see they all start the same so we can't eliminate one just yet.. Lets go with the second one, x^2 times -1 and we will get -1x^2 now remember that we ave to find the next term and subtract or add it to this one in order to find the next number in the line... so lets go ahead and multiply 6x times 3x and get 18x^2 now lets add that to -1x^2 and we will get 17x^2, now lets see if we can eliminate one now.. as a matter of fact if you take notice knowing that our next term is positive 17x^2 we can know that practically all are eliminated execpt the first one.. this is because the second one is 17x^2 but it negavtive and ours is positive so that can't be, and the others are 19 and our number is 17 so those won't fit either but lets keep going to make sure. lets multiply 6x times -1 and get -6x, now 9 times 3x to get 27x lets add that one and -6x to get 21x that is our third number. finally multiply 9 times -9 and you will get -9 this is your final number...
So your answer is the first option hope this helps
