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kumpel [21]
2 years ago
8

Help me pretty pleaseeee

Mathematics
2 answers:
Scrat [10]2 years ago
7 0

Answer:

It's decreasing as 5 is a negative and a negatives goes down.

IgorLugansk [536]2 years ago
4 0
Decreasing by 5 and negative goes down
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Find the value of x and y.
Mrrafil [7]

Answer:

Step-by-step explanation:

CD and AB are parallel; DB transverse

∠D + ∠B = 180     {co interior angles}

112 + 27 + y = 180

139 + y = 180

y = 180 - 139

y = 41

In ΔABC,

49 + x + y = 180   ( sum of all angles of triangle}

49 + x + 41 = 180

90 + x = 180

x = 180 - 90

x = 90

5 0
3 years ago
All Seasons Plumbing has two service trucks that frequently need repair. If the probability the first truck is available is 0.75
oksano4ka [1.4K]

Answer: There is a probability of 0.05 that there is neither truck is available.

Step-by-step explanation:

Since we have given that

Probability that the first truck is available = 0.75

Probability that the second truck is available = 0.50

Probability that both trucks are available = 0.30

So, probability that either first truck or second truck is available is given by

P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\P(A\cup B)=0.75+0.50-0.30\\\\P(A\cup B)=0.95

We need to find the probability that neither truck is available.

so, P(A∪B)'=1-P(A∪B)

P(A\cup B)'=1-0.95=0.05

Hence, there is a probability of 0.05 that there is neither truck is available.

4 0
4 years ago
47. Which of the following represents 0.2% of 1/5?
erica [24]

First think of what 0.2% is as a fraction,

0.2\%=\frac{0.2}{100}=\frac{2\cdot10^{-1}}{10^2}=\frac{2}{10^3}=\frac{2}{1000}

Now multiply the fraction by a fifth,

\frac{2}{1000}\cdot\frac{1}{5}=\frac{2}{5000}

Which then simplifies to,

\frac{2}{5000}=\boxed{\frac{1}{2500}}

Hope this helps :)

8 0
3 years ago
Find the value of x in the figure
Svetach [21]
I Might know what your talking about. . . .if so then it is A) 40 degrees
4 0
4 years ago
What is the rise of the points (0,-4) and (0,5)
tatiyna

rise is 5 - - 4 = 5 + 4.

Thus, the rise of the points is 9.

8 0
3 years ago
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