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Kobotan [32]
3 years ago
11

Elio makes candles that are 14\text{ cm}14 cm14, start text, space, c, m, end text tall. Each candle burns 888 hours before goin

g out. He is wondering how many hours a 21\text{ cm}21 cm21, start text, space, c, m, end text tall candle can burn for.
He assumes that the relationship between the height of a candle and number of hours it burns (h)(h)left parenthesis, h, right parenthesis is proportional.
How long a 21 \text{ cm}21 cm21, start text, space, c, m, end text tall candle can burn for?
Mathematics
2 answers:
erastova [34]3 years ago
5 0

Answer:

12 Hours

Step-by-step explanation:

h=21/14*8

h=12 hours

Maurinko [17]3 years ago
4 0

Answer:   21 cm candle burns for 12 hours.

Step-by-step explanation:

Equation to show proportional relation between two quantities x and y

 : \dfrac{x_1}{y_1}=\dfrac{x_2}{y_2}

According to the given situation :

Let x_1=14\ cm,\ y_1=8\ hours,\ x_21\ cm,\ y_2=y

Put these values in equation , we get

\dfrac{14}{8}=\dfrac{21}{y}\\\\\Rightarrow\ y=\dfrac{21\times8}{14}=12\ hours

Hence, 21 cm candle burns for 12 hours.

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egoroff_w [7]

Answer:

\begin{array}{cc}\text{Mathematical expression}&\text{Translation}\\ \\xy&\text{The product of two numbers}\\ \\\dfrac{x}{y}&x\text{ divided by }y\\ \\x-y&x\text{ minus }y\\ \\x+y&\text{the sum of }x\text{ and }y\\ \\y-x&x\text{ subtracted from }y\\ \\y:x&y\text{ divided by } x\\ \\x+y=6&\text{the sum of two numbers is 6}\\ \\xy=6&\text{the product of two numbers is 6}\\ \\6x=y&\text{6 times a number equals }y\\ \\y=x-6&\text{6 less than a number is }y\end{array}

Step-by-step explanation:

\begin{array}{cc}\text{Mathematical expression}&\text{Translation}\\ \\xy&\text{The product of two numbers}\\ \\\dfrac{x}{y}&x\text{ divided by }y\\ \\x-y&x\text{ minus }y\\ \\x+y&\text{the sum of }x\text{ and }y\\ \\y-x&x\text{ subtracted from }y\\ \\y:x&y\text{ divided by } x\\ \\x+y=6&\text{the sum of two numbers is 6}\\ \\xy=6&\text{the product of two numbers is 6}\\ \\6x=y&\text{6 times a number equals }y\\ \\y=x-6&\text{6 less than a number is }y\end{array}

6 0
3 years ago
Can you plz help on this
svp [43]
No sorry i can’t do that
8 0
3 years ago
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How many elements are in the union of five sets if the sets contain 10,000 elements each, each pair of sets has 1000 common elem
masya89 [10]

Answer:

40951

Step-by-step explanation:

Using the principles of inclusion - Exclusion

Where C(n,r)=n!/(n-r)!r!

Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000

Total Number of elements in each pair including number repetition of sets is given as

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Number of elements in each triple of sets is given as

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Number of elements in every four sets

=(10) × C(5, 4)=50

Number of elements in every one set

(1) × C(5, 5)=1

Therefore total number of unique elements=50000-10000+1000-50+1

=40951

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