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4 years ago

I WILL MARK THE BRAINLEST IF U W\ANSWER ASAP what 37x56x12x13 pls

Mathematics

2 answers:

Arada [10]4 years ago

4 0

Answer:

323232

Step-by-step explanation:

Calculators are good for stuff like this

aev [14]4 years ago

3 0

Answer:

323,232

Step-by-step explanation:

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Here are the first four terms of a quadratic sequence.

Llana [10]

Answer:

a = 3, b = 1, c = - 3

Step-by-step explanation:

Substitute n = 1, 2, 3 into the n th term

a + b + c = 1 → (1)

4a + 2b + c = 11 → (2)

9a + 3b + c = 27 → (3)

Subtract (1) from (2) term by term to eliminate c

Subtract (2) from (3) term by term to eliminate c

3a + b = 10 → (4)

5a + b = 16 → (5)

Subtract (4) from (5) term by term to eliminate b

2a = 6 ( divide both sides by 2 )

a = 3

Substitute a = 3 into (4) and evaluate for b

3(3) + b = 10

9 + b = 10 ( subtract 9 from both sides )

b = 1

Substitute a = 3, b = 1 into (1) and evaluate for c

3 + 1 + c = 1

4 + c = 1 ( subtract 4 from both sides )

c = - 3

Then a = 3, b = 1 and c = - 3

4 0

3 years ago

WILL GIVE BRAINLIST AS SOON AS I CAN... is this 6??

Salsk061 [2.6K]

The answer is angle 3

6 0

3 years ago

A 500 gallon tank initially contains 200 gallons of water with 5 lbs of salt dissolved in it. Water enters the tank at a rate of

Lapatulllka [165]

Until the concerns I raised in the comments are resolved, you can still set up the differential equation that gives the amount of salt within the tank over time. Call it $A(t)$ .

Then the ODE representing the change in the amount of salt over time is

$\dfrac{\mathrm dA}{\mathrm dt}=\text{rate in}-\text{rate out}$
$\dfrac{\mathrm dA}{\mathrm dt}=\dfrac{2\text{ gal}}{1\text{ hr}}\times\dfrac{\frac15(1+\cos t)\text{ lbs}}{1\text{ gal}}-\dfrac{2\text{ gal}}{1\text{ hr}}\times\dfrac{A(t)\text{ lbs}}{500+(2-2)t}$
$\dfrac{\mathrm dA}{\mathrm dt}=\dfrac25(1+\cos t)-\dfrac1{250}A(t)$

and this with the initial condition $A(0)=5$

You have

$\dfrac{\mathrm dA}{\mathrm dt}+\dfrac1{250}A(t)=\dfrac25(1+\cos t)$
$e^{t/250}\dfrac{\mathrm dA}{\mathrm dt}+\dfrac1{250}e^{t/250}A(t)=\dfrac25e^{t/250}(1+\cos t)$
$\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/250}A(t)\right]=\dfrac25e^{t/250}(1+\cos t)$

Integrating both sides gives

$e^{t/250}A(t)=100e^{t/250}\left(1+\dfrac1{62501}\cos t+\dfrac{250}{62501}\sin t\right)+C$
$A(t)=100\left(1+\dfrac1{62501}\cos t+\dfrac{250}{62501}\sin t\right)+Ce^{-t/250}$

Since $A(0)=5$ , you get

$5=100\left(1+\dfrac1{62501}\right)+C\implies C=-\dfrac{5937695}{62501}$

so the amount of salt at any given time in the tank is

$A(t)=100\left(1+\dfrac1{62501}\cos t+\dfrac{250}{62501}\sin t\right)-\dfrac{5937695}{62501}e^{-t/250}$

The tank will never overflow, since the same amount of solution flows into the tank as it does out of the tank, so with the given conditions it's not possible to answer the question.

However, you can make some observations about end behavior. As $t\to\infty$ , the exponential term vanishes and the amount of salt in the tank will oscillate between a maximum of about 100.4 lbs and a minimum of 99.6 lbs.

5 0

4 years ago

Please helppppp. "Elizabeth and Mimi are playing a factor game. Elizabeth told Mimi that she was thinking of a mystery number th

aksik [14]

Well if you actually think about it on a multiple chart this would go on forever so i believe the best anwser would be 1

4 0

4 years ago

Adam was going to sell all of his stamp collection to buy a video game. After selling half of them he changed his mind and did n

Roman55 [17]

He would have 21 before he bought the 10 stamp because 31-10=21

6 0

4 years ago