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3 years ago

Y over 5 minus 6 over one Equals 8

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

3 0

Answer:

The answer is one because 6 divided by 1 is 6 and 6 - 5 is equal to one

Step-by-step explanation:

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A school club is comparing prices at two movie theaters. Theater 1 charges $7.50 for a movie ticket and $5.75 per item at the co

salantis [7]

Step-by-step explanation:

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3 years ago

Naomi has earned $54 mowing lawns the past two days. she worked 2 1/2 hours yesterday and 4 1/4 hours today. if naomi is paid th

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She earns about 7.71

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2 years ago

Samuel and Christopher go to the movie theater and purchase refreshments for their friends. Samuel spends a total of $34.00 on 6

Llana [10]

Answer:

The system of equations is :

6 p + 4 d = 34

12 p + 7 d = 66.25

The price of a drink is $1.75

Step-by-step explanation:

Assume that the price of one bag of popcorn is $p and the price of a drink is $d

∵ Samuel spends a total of $34 on 6 bags of popcorn and

4 drinks

- Multiply p by 6 and d by 4, then add the products and equate

the sum by 34

∴ 6 p + 4 d = 34 ⇒ (1)

∵ Christopher spends a total of $66.25 on 12 bags of popcorn

and 7 drinks

- Multiply p by 12 and d by 7, then add the products and equate

the sum by 66.25

∴ 12 p + 7 d = 66.25 ⇒ (2)

The system of equations is :

6 p + 4 d = 34

12 p + 7 d = 66.25

Now let us solve it

Multiply equation (1) by -2 to make the coefficients of p in the two equations equal in values and opposite in signs to eliminate it

∵ -12 p - 8 d = - 68 ⇒ (3)

- Add equations (2) and (3)

∴ - d = - 1.75

- Divide both sides by -1

∴ d = 1.75

The price of a drink is $1.75

7 0

3 years ago

Find the mass and the center of mass of a wire loop in the shape of a helix (measured in cm: x = t, y = 4 cos(t), z = 4 sin(t) f

Sholpan [36]

Answer:

Mass

$\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)$

Center of mass

Coordinate x

$\displaystyle\frac{(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Coordinate y

$\displaystyle\frac{16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Coordinate z

$\displaystyle\frac{-16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Step-by-step explanation:

Let W be the wire. We can consider W=(x(t),y(t),z(t)) as a path given by the parametric functions

x(t) = t

y(t) = 4 cos(t)

z(t) = 4 sin(t)

for 0 ≤ t ≤ 2π

If D(x,y,z) is the density of W at a given point (x,y,z), the mass m would be the curve integral along the path W

$m=\displaystyle\int_{W}D(x,y,z)=\displaystyle\int_{0}^{2\pi}D(x(t),y(t),z(t))||W'(t)||dt$

The density D(x,y,z) is given by

$D(x,y,z)=x^2+y^2+z^2=t^2+16cos^2(t)+16sin^2(t)=t^2+16$

on the other hand

$||W'(t)||=\sqrt{1^2+(-4sin(t))^2+(4cos(t))^2}=\sqrt{1+16}=\sqrt{17}$

and we have

$m=\displaystyle\int_{W}D(x,y,z)=\displaystyle\int_{0}^{2\pi}D(x(t),y(t),z(t))||W'(t)||dt=\\\\\sqrt{17}\displaystyle\int_{0}^{2\pi}(t^2+16)dt=\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)$

The center of mass is the point $(\bar x,\bar y,\bar z)$

where

$\bar x=\displaystyle\frac{1}{m}\displaystyle\int_{W}xD(x,y,z)\\\\\bar y=\displaystyle\frac{1}{m}\displaystyle\int_{W}yD(x,y,z)\\\\\bar z=\displaystyle\frac{1}{m}\displaystyle\int_{W}zD(x,y,z)$

We have

$\displaystyle\int_{W}xD(x,y,z)=\sqrt{17}\displaystyle\int_{0}^{2\pi}t(t^2+16)dt=\\\\=\sqrt{17}(\displaystyle\frac{(2\pi)^4}{4}+32\pi)$

$\bar x=\displaystyle\frac{\sqrt{17}(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)}=\displaystyle\frac{(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

$\displaystyle\int_{W}yD(x,y,z)=\sqrt{17}\displaystyle\int_{0}^{2\pi}4cos(t)(t^2+16)dt=\\\\=16\sqrt{17}\pi$

$\bar y=\displaystyle\frac{16\sqrt{17}\pi}{\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)}=\displaystyle\frac{16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

$\displaystyle\int_{W}zD(x,y,z)=4\sqrt{17}\displaystyle\int_{0}^{2\pi}sin(t)(t^2+16)dt=\\\\=-16\sqrt{17}\pi$

$\bar z=\displaystyle\frac{-16\sqrt{17}\pi}{\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)}=\displaystyle\frac{-16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

3 0

2 years ago

a bag contains 2 coins, one fair and the other with 2 heads. you pick 1 coin at random and flip it. what is the probability that

Nezavi [6.7K]

The probability that you picked the fair coin given that the outcome of the toss was heads is 1/3.

There is a one in two chance of drawing the fair coin. The chances of flipping heads again are 1 in 2. As a result, there is a 1 in 4 chance that the coin will land on heads.

There is a one in two chance of drawing the trick coin. The probability of flipping heads is then 2 to 1. As a result, there is a 2 in 4 chance that the coin will land on heads.

When each is multiplied by four, the resulting integers are

fair: 1 and trick: 2

and overall results: 3. (fair and tails is not counted)

The likelihood of a fair coin is one in three.

The likelihood that the chosen coin will show heads and be the fair coin is 33.333%.

To learn more about probability

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4 0

1 year ago