No solution since absolute value can't be equal to negative numbers
PLEASE GIVE BRAINLIEST
Answer:
64,120,136
I think
Step-by-step explanation:
A) 12, 10, 7,3,<br>
Rule:<br>
b) 1,3,9, 27,<br>
Rule:<br>
I<br>
c) 4, 19, 34, 49<br>
Rule:
sergejj [24]
A the rule would be -1 times X
B the rule would be x3
C the rule would be +15
Solution:
This problem is a permutation because the order matters here. This means that choosing A as King, B as Knight, C as Bishop and D as Rook results in a different arrangement from B as King, A as Knight, D as Bishop and C as Rook. We would count them both because in the first case A is King, but in the second case A is Knight.
Therefore, the possible number of ways are given below:

Hence there will be 93024 ways 19 members of a chess club fill the offices of King, Knight, Bishop, and Rook.
Answer:
Step-by-step explanation:
4)
28 in base 10
base 5=28*2=56
base 2=28*5=140
5)
7 in base 10
base 5=7*2=14
base 2=7*5=35
6)
100 in base 2
base 5=100*5/2=500/2=250
base 10=100*5=500
7)
10010 in base 2
base 5=10010*5/2=50050/2=25025
base 10=10010*5=50050
8)
10111 in base 2
base 5=10111*5/2=50555/2=25277.5
base 10=100*5=50555