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jek_recluse [69]
3 years ago
15

I need help figuring out the answers

Mathematics
1 answer:
ioda3 years ago
8 0
Wait so do you need help or me to check them?
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What is the solution set of -xl = -10?
lorasvet [3.4K]

No solution since absolute value can't be equal to negative numbers

PLEASE GIVE BRAINLIEST

8 0
2 years ago
Read 2 more answers
Find the Pythagorean Triple (a,b,c) using the terms (x²-y², 2xy, x² +y²) for x >y> 0
Lemur [1.5K]

Answer:

64,120,136  

I think

Step-by-step explanation:

8 0
3 years ago
A) 12, 10, 7,3,<br> Rule:<br> b) 1,3,9, 27,<br> Rule:<br> I<br> c) 4, 19, 34, 49<br> Rule:
sergejj [24]
A the rule would be -1 times X
B the rule would be x3
C the rule would be +15
5 0
3 years ago
In how many ways can the 19 members of a chess club fill the offices of​ King, Knight,​ Bishop, and​ Rook?
goldfiish [28.3K]

Solution:

This problem is a permutation because the order matters here. This means that choosing A as King, B as Knight, C as Bishop and D as Rook results in a different arrangement from B as King, A as Knight, D as Bishop and C as Rook. We would count them both because in the first case A is King, but in the second case A is Knight.

Therefore, the possible number of ways are given below:

19P4=\frac{19!}{(19-4)!} =\frac{19 \times 18 \times 17 \times 16 \times 15!}{15!} =19 \times 18 \times 17 \times 16 =93024

Hence there will be 93024 ways 19 members of a chess club fill the offices of King, Knight, Bishop, and Rook.

3 0
3 years ago
Please Complete The rest.
AfilCa [17]

Answer:

Step-by-step explanation:

4)

28 in base 10

base 5=28*2=56

base 2=28*5=140

5)

7 in base 10

base 5=7*2=14

base 2=7*5=35

6)

100 in base 2

base 5=100*5/2=500/2=250

base 10=100*5=500

7)

10010 in base 2

base 5=10010*5/2=50050/2=25025

base 10=10010*5=50050

8)

10111 in base 2

base 5=10111*5/2=50555/2=25277.5

base 10=100*5=50555

4 0
3 years ago
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