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natka813 [3]
3 years ago
7

Which element is most chemically similar to chlorine

Chemistry
1 answer:
Rus_ich [418]3 years ago
5 0
Halogen, Fluorine, or bromine
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in the reaction, 2h2 o2 --> 2h2o, how many hydrogen molecules are needed to produce two water molecules?a. 1b. 2c. 3d. 4
natali 33 [55]
The balanced reaction between Hydrogen and Oxygen to form Water:

 2H₂ + O₂  →  2H₂O

From the equation it already states that:

2 molecules of Hydrogen H₂ are needed to produce 2 molecules of Water H₂O

So the answer is 2.

Option B.
7 0
3 years ago
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What are the complex organic compounds concentrated in grapes' skin, pits and stems that gives red wines their characteristic dr
SashulF [63]
Your team has been hired to advice a fictional
agribusiness company named "Merced Grapes
and Wine", or MGW. MGW is located in the
Merced county, California, where the economy is
driven by agriculture, and works with many grape
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MGW has an annual revenue of $35,000,000
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They spend per year $12,000,000 in logistics,
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I need help with option 3 shown below:
Option #3. Extraction of bioactive compounds
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7 0
3 years ago
Which metal can replace another metal in a reaction?
deff fn [24]

Answer:

O A. A metal higher on the activity series list will replace one that is

lower.

4 0
3 years ago
If 13.2 kg of Al 2 O 3 ( s ) , 50.4 kg of NaOH ( l ) , and 50.4 kg of HF ( g ) react completely, how many kilograms of cryolite
Elodia [21]

Answer : The mass of cryolite produced will be, 54.38 kg

Solution : Given,

Mass of Al_2O_3 = 13.2 kg  = 13200 g

Mass of NaOH = 50.4 kg  = 50400 g

Mass of HF = 50.4 kg  = 50400 g

Molar mass of Al_2O_3 = 101.9 g/mole

Molar mass of NaOH = 40 g/mole

Molar mass of HF = 20 g/mole

Molar mass of Na_3AlF_6 = 209.9 g/mole

First we have to calculate the moles of Al_2O_3,NaOH and HF.

\text{ Moles of }Al_2O_3=\frac{\text{ Mass of }Al_2O_3}{\text{ Molar mass of }Al_2O_3}=\frac{13200g}{101.9g/mole}=129.54moles

\text{ Moles of }NaOH=\frac{\text{ Mass of }NaOH}{\text{ Molar mass of }NaOH}=\frac{50400g}{40g/mole}=1260moles

\text{ Moles of }HF=\frac{\text{ Mass of }HF}{\text{ Molar mass of }HF}=\frac{50400g}{20g/mole}=2520moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

Al_2O_3+6NaOH+12HF\rightarrow 2Na_3AlF_6+9H_2O

From the balanced reaction we conclude that

The mole ratio of Al_2O_3,NaOH and HF is, 1 : 6 : 12

And, the ratio of given moles of Al_2O_3,NaOH and HF is, 129.54 : 1260 : 2520

From this we conclude that, NaOH,HF is an excess reagent because the given moles are greater than the required moles and Al_2O_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Na_3AlF_6

From the reaction, we conclude that

As, 1 mole of Al_2O_3 react to give 2 mole of Na_3AlF_6

So, 129.54 moles of Al_2O_3 react to give 129.54\times 2=259.08 moles of Na_3AlF_6

Now we have to calculate the mass of Na_3AlF_6

\text{ Mass of }Na_3AlF_6=\text{ Moles of }Na_3AlF_6\times \text{ Molar mass of }Na_3AlF_6

\text{ Mass of }Na_3AlF_6=(259.08moles)\times (209.9g/mole)=54380.892g=54.38kg

Thus, the mass of cryolite produced will be, 54.38 kg

5 0
3 years ago
Which organisms are consumers?
masya89 [10]

Answer: snake grass hopper and monkey

Explanation: i took the test and this is what i got

8 0
3 years ago
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