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Wewaii [24]
3 years ago
9

The ionization of pure water forms _____.

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer: The ionization of pure water forms <u><em>hydroxide and hydronium ions.</em></u>

Explanation:

Ionization is a reaction in the pure water in which water breaks down into its constituting ions that hydronium ion and hydroxide ions.

H_2O+H_2O\rightleftharpoons H_3O^++OH^-

One molecule of water looses its proton to form hydroxide ion and l=the lost protons get associated with another water molecule to form hydronium ion.

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The number of _______ in an atom of an element is the element's atomic number.
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The atomic mass of element A is 35.45 amu. A 28.54 g sample of A combines with 85.42 g of another element B to form a compound A
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The atomic mass of element B is 106.1 amu.

Given:

  • The atomic mass of element A is 35.45 amu.
  • A +B → AB
  • 28.54 g sample of A combines with 85.42 g of another element B

To find:

The atomic mass of element B.

Solution:

The mass of element A = 28.54 g

The atomic mass of element A = 35.45 amu = 35.45 g/mol

Moles of element A :

= \frac{28.54 g}{35.45 g/mol}=0.8051 mol

A +B → AB

According to reaction, one mole of A combines with 1 mole of B , then 0.8051 moles of A will combine with:

=\frac{1}{1}\times 0.8051 mol=0.8051 \text{ mol of B}

Moles of B element = 0.8051 mol

Mass of element B used = 85.42 g

The atomic mass of element B =M

0.8051 mol=\frac{85.42 g}{M}\\M=\frac{85.42 g}{0.8051 mol}=106.1 g/mol = 106.1 amu

The atomic mass of element B is 106.1 amu.

Learn more about moles of substance here:

brainly.com/question/2293005?referrer=searchResults

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