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Wewaii [24]
3 years ago
9

The ionization of pure water forms _____.

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer: The ionization of pure water forms <u><em>hydroxide and hydronium ions.</em></u>

Explanation:

Ionization is a reaction in the pure water in which water breaks down into its constituting ions that hydronium ion and hydroxide ions.

H_2O+H_2O\rightleftharpoons H_3O^++OH^-

One molecule of water looses its proton to form hydroxide ion and l=the lost protons get associated with another water molecule to form hydronium ion.

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Coffee is a mixture because it is a mixture of many compounds
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3 years ago
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An aqueous nacl solution is made using 112 g of nacl diluted to a total solution volume of 1.00 l. calculate the molarity, molal
worty [1.4K]
Q1)
molarity is defined as the number of moles of solute in 1 L of solution.
the NaCl solution volume is 1.00 L
number of moles NaCl  = NaCl mass present / molar mass of NaCl 
NaCl moles = 112 g / 58.5 g/mol = 1.91 mol 
the number of moles of NaCl in 1.00 L of solution is - 1.91 mol 
therefore molarity of NaCl is 1.91 M

Q2) 
molality is defined as the number of moles of solute in 1 kg of solvent.
density is mass per volume. 
density of the solution is 1.08 g/mL. 
therefore mass of the solution is = density x volume 
mass = 1.08 g/mL x 1000 mL = 1080 g
since we have to find the moles in 1 kg of solvent 
mass of solvent = 1080 g - 112 g = 968 g
number of moles of NaCl in 968 g of solvent - 1.91 mol 
therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg
molality of NaCl solution is 1.97 mol/kg


Q3) 
mass percentage is the percentage of mass of solute by total mass of the solution 
mass percentage of solution = mass of solute / total mass of the solution 
mass of solute = 112 g
total mass of solution = 1080 g
mass % of NaCl = 112 g / 1080 g x 100%
therefore mass % of NaCl = 10.4 %
answer is 10.4 %
5 0
3 years ago
Where in the periodic table would you find elements with the same number of energy levels?
kifflom [539]

Answer:

b

Explanation:

6 0
4 years ago
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Consider the reaction: Mg(OH)₂ (s) ⇌ Mg²⁺ (aq) + 2 OH⁻ (aq)
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6 0
4 years ago
A reaction rate increases by a factor of 655 in the presence of a catalyst at 37°C. The activation energy of the original pathwa
irinina [24]

For a reaction rate that increases by a factor of 655 in the presence of a catalyst at 37°C, the activation energy of the new pathway  is mathematically given as

Ea2=89.28JKoule/mol

<h3>What is the activation energy of the new pathway, all other factors being equal?</h3>

Generally, the equation for the rate constant  is mathematically given as

K=Ae^{Ea1/Rt}

Therefore

\frac{1}{655}=\frac{1}{8.31*3.10}(Ea2-105000)

Ea2=89286.083Joule/mol

In conclusion, the activation energy

Ea2=89.28JKoule/mol

Read more about Energy

brainly.com/question/13439286

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3 years ago
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