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Leto [7]
3 years ago
7

A fatty substance that does not dissolve in water

Chemistry
1 answer:
Hitman42 [59]3 years ago
4 0
The substance is lipid substance
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Write structural formulas for each of the possible isomers of n-hexene that are formed by moving the position of the double bond
dem82 [27]

Answer : The structural formulas for each of the possible isomers of n-hexene are shown below.

Explanation :

Isomer : It is defined as a molecule have the same molecular formula but the different chemical structure.

There are three structural isomers of n-hexene that is based on the location of the double-bonded carbon atoms with the other atoms.

In n-hexane, 'n' shows that the chain should be straight chain there is no branching.

The three structural isomers of n-hexene are:

(1) 1-hexene

(2) 2-hexene

(3) 3-hexene

Thus, the structural formulas for each of the possible isomers of n-hexene are shown below.

5 0
3 years ago
12.0 moles of gas are in a 6.00 L tank at 23.4 ∘C . Calculate the difference in pressure between methane and an ideal gas under
mote1985 [20]
I didn't get it niether sorry
8 0
3 years ago
Define saturated and unsaturated fats​
saul85 [17]

Answer:

SATURATED: Saturated fat is a type of fat in which the fatty acid chains have all or predominantly single bonds.

UNSATURATED: Unsaturated fats are loosely packed. They tend to be liquid at room temperature.

<em>There are two main types of unsaturated fat:</em>

<u>Monounsaturated</u>

<u>Polyunsaturated</u>

8 0
3 years ago
How many moles are in 3.555 g of c2h2?
Juli2301 [7.4K]

Answer:

0.13653499904751903

Explanation:

Convert Units .com

5 0
3 years ago
the rate constant for the decomposition of acetaldehyde, ch3cho, to methane, ch4, and carbon monoxide, co, in the gas phase is 1
Mademuasel [1]

The rate constant for the decomposition of acetaldehyde, CH₃CHO, to methane, CH₄, and carbon monoxide, CO, in the gas phase is 1.10 × 10² m⁻¹ s⁻¹ at 703.7 k and 4.90 x 10⁻² m⁻¹ s⁻¹ at 865 k.The activation energy for this decomposition in KJ/mole is 154.303

To determine the activation energy of a reaction (Ea) from two reaction rates (k₁ and k₂) at two different temperatures (T₁ and T₂).

we use the equation -

<u>k₂</u> = <u>Eₐ </u> x ( <u>1  </u> -  <u>1  )</u>

k₁     R       T₁    T₂

Where,

R is the gas constant (8.3145 J/mol.K).

We have -

k₁= 1.10 x 10⁻²  m⁻¹ s⁻¹

T₁= 703.7 K

k₂= 4.90 x 10⁻² m⁻¹ s⁻¹  

T₂= 865 K

Putting the values in the equation -

<u>4.90 x 10⁻² m⁻¹ s¹</u> =<u>          Ea             </u>  x ( <u>     1      </u>  -  <u>     1    )</u>

1.10 x 10⁻² m⁻¹ s⁻¹   (8.3145 J/K.mol)      703.7 K      865 K

Ea = (4<u>.90 x 10⁻² m⁻¹ s⁻¹</u>) / ( <u>     1      </u> -  <u>      1    </u> <u>)</u> x (8.3145 J/K.mol)

         1.10 x 10⁻² m⁻¹ s⁻¹        703.7 K    851 K

Ea = 154303 J/mol

When divided by 1000,

Ea in KJ/mol = 154.303 KJ/mol

To learn more about activation energy,

brainly.com/question/8911926

#SPJ4

3 0
1 year ago
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