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Radda [10]
4 years ago
12

Enter the chemical formula of a binary molecular compound of hydrogen and a Group 6A element that can reasonably be expected to

be less acidic in aqueous solution than H2Se, e.g. have a smaller Ka .

Chemistry
1 answer:
NARA [144]4 years ago
3 0

Answer:

Any binary molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.

Explanation:

Going down in a group increases the atomic radius and a greater atomic radius implyes greater ionic radius.  

When ionization takes place in these compounds they yelds protons (hidrogen ion) and an lewis base (anion). The greater the ionic radius the greater its stability, thus the periodic tendency is increaing the acidity of binary hidrogen compounds when going down a group. On the other hand going up a group decreases acidity, so any molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.

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Iron is obtained by reaction of hematite (Fe2O3) with carbon monoxide. From the balanced reaction below, how many grams of iron
laila [671]

Answer: 2755.2 g of Fe will be produced from 24.6 mol of haematite.

Explanation:

The balanced chemical equation is:

Fe_2O_3+3CO\rightarrow 2Fe+3CO_2  

According to stoichiometry :

1 mole of Fe_2O_3 produce = 2 moles of Fe

Thus 24.6 moles of Fe_2O_3 will produce=\frac{2}{1}\times 24.6=49.2moles  of Fe  

Mass of Fe=moles\times {\text {Molar mass}}=49.2moles\times 56g/mol=2755.2g

Thus 2755.2 g of Fe will be produced from 24.6 mol of haematite.

3 0
3 years ago
The answer is b saturated
NeX [460]

Answer:

the answer for what?

Explanation:

the answer is b saturated

3 0
3 years ago
what criteria are likely to dictate certain pairs of elements to undergo ionic bonding and others covalent bonding?
Paha777 [63]

Answer:

If one element is a metal and the other element is a non metal

Explanation:

Ionic bonds are formed between metals and non metals. The nonmetal atom receives electron(s) from a metal atom to form an ionic substance. This means that ionic substances are basically an ion pair.

Covalent bonds are mostly formed between two nonmetals. These elements share electrons with each other in order to form the compound.

7 0
3 years ago
If 45.0 liters of oxygen is measured at 24.0C, what would be its volume at standard temperature?
nika2105 [10]

The volume of the oxygen gas at standard temperature  is 41.36 liters.

The given parameters;

  • <em>initial volume of oxygen, V₁ = 45 L</em>
  • <em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
  • <em>standard temperature, T₂ = 0 ⁰C = 273 K</em>

<em />

The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;

\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1 T_2}{T_1} \\\\V_2 = \frac{45 \times 273}{297} \\\\V_2 = 41.36 \ L

Thus, the volume of the oxygen gas at standard temperature  is 41.36 L.

Learn more here:brainly.com/question/16927784

6 0
3 years ago
Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re
borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

V = \frac{nRT}{P}

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

3 0
3 years ago
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