Answer: 2755.2 g of
will be produced from 24.6 mol of haematite.
Explanation:
The balanced chemical equation is:
According to stoichiometry :
1 mole of
produce = 2 moles of 
Thus 24.6 moles of
will produce=
of
Mass of 
Thus 2755.2 g of
will be produced from 24.6 mol of haematite.
Answer:
the answer for what?
Explanation:
the answer is b saturated
Answer:
If one element is a metal and the other element is a non metal
Explanation:
Ionic bonds are formed between metals and non metals. The nonmetal atom receives electron(s) from a metal atom to form an ionic substance. This means that ionic substances are basically an ion pair.
Covalent bonds are mostly formed between two nonmetals. These elements share electrons with each other in order to form the compound.
The volume of the oxygen gas at standard temperature is 41.36 liters.
The given parameters;
- <em>initial volume of oxygen, V₁ = 45 L</em>
- <em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
- <em>standard temperature, T₂ = 0 ⁰C = 273 K</em>
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The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;

Thus, the volume of the oxygen gas at standard temperature is 41.36 L.
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Answer:
1.65 L
Explanation:
The equation for the reaction is given as:
A + B ⇄ C
where;
numbers of moles = 0.386 mol C (g)
Volume = 7.29 L
Molar concentration of C = 
= 0.053 M
A + B ⇄ C
Initial 0 0 0.530
Change +x +x - x
Equilibrium x x (0.0530 - x)
![K = \frac{[C]}{[A][B]}](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BC%5D%7D%7B%5BA%5D%5BB%5D%7D)
where
K is given as ; 78.2 atm-1.
So, we have:
![78.2=\frac{[0.0530-x]}{[x][x]}](https://tex.z-dn.net/?f=78.2%3D%5Cfrac%7B%5B0.0530-x%5D%7D%7B%5Bx%5D%5Bx%5D%7D)


Using quadratic formula;

where; a = 78.2 ; b = 1 ; c= - 0.0530
=
or 
=
or 
= 0.0204 or -0.0332
Going by the positive value; we have:
x = 0.0204
[A] = 0.0204
[B] = 0.0204
[C] = 0.0530 - x
= 0.0530 - 0.0204
= 0.0326
Total number of moles at equilibrium = 0.0204 + 0.0204 + 0.0326
= 0.0734
Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT
if we make V the subject of the formula; we have:

where;
P (pressure) = 1 atm
n (number of moles) = 0.0734 mole
R (rate constant) = 0.0821 L-atm/mol-K
T = 273.15 K (fixed constant temperature )
V (volume) = ???

V = 1.64604
V ≅ 1.65 L