Cu + Cl2 → CuCl
copper+chloride →copper(ll)chloride
The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.
<h3>What is precipitate?</h3>
Precipitates are the crystal type formation, when the solute is no more dissolving in the solvent.
Imagine mixing 1 tablespoon of Epsom salt with 2 cups of ammonia, the reaction is
2NH₃ + MgSO₄ + 2H₂O → Mg(OH)₂ + (NH₄)₂SO₄
The amount of precipitate produced will be proportional to the amount of NH₃ reacted with water to produce NH₄OH.
Learn more about precipitate.
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I think O and Cl will form covalent bonds since they are both non-metals and don't have a large enough difference in electronegativities to create an ionic bond.
I hope this helps. Let me know if anything is unclear.
I assume you mean 'structure' :)
Metals undergo metallic bonding. In this type of bond, metal atoms loose their valence electrons (that become delocalised). This type of bonding creates a regular layered lattice with positive metal ions and a sea of delocalised electrons floating between the layers. These layers slide over each other and results in metals being both malleable and ductile.
Hope it helps!
The specific heat capacity of copper metal : 0.390 J/g °C
<h3>Further explanation</h3>
Given
25 g metal
Δt metal = 18°C
15 g water
Δt water = 2.8 °C
Required
The specific heat capacity of copper metal
Solution
Q out = Q in
Q releases by metal = Q absorbed by water
m.c.Δt metal = m.c.Δt water(c water = 4.184 J/g °C)
25 x c x 18 = 15 x 4.18 x 2.8
c = 0.390 J/g °C