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iVinArrow [24]
3 years ago
15

Which of the following most likely happens when the volume of a gas increases the number of collisions of gas particles remains

same. The number of collisions of gas particles increases. The pressure of the gas remains the same. The pressure of the gas decreases
Chemistry
2 answers:
ch4aika [34]3 years ago
8 0

Answer:

D. The pressure of the gas decreases!

Explanation:

According to Boyle's Law, there is an inverse relationship between the volume of a gas and its pressure!

So, if the volume of a gas increases, its pressure will decrease; the same thing will happen if the pressure of the gas increases -- the volume will decrease!

↑P↓V and ↓P↑V    <---- this is what it would look like visually!!

Hope this helps! :)

lord [1]3 years ago
5 0

When the collision of gas particles and the volume of the gas stay the same it causes a chemical.

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3 years ago
Calculate the pKa of lactic acid (CH3CH(OH)COOH) given the following information. 3.005 grams of potassium lactate are added to
snow_lady [41]

Answer:

\displaystyle \text{p} K_a \approx 3.856

Explanation:

Because 3.005 grams of potassium lactate is added to 100. mL of solution, its concentration is:


\displaystyle \begin{aligned} \left[ \text{KC$_3$H_$_5$O$_3$}\right]  & = \frac{3.005\text{ g KC$_3$H_$_5$O$_3$}}{100.\text{ mL}} \cdot \frac{1\text{ mol KC$_3$H_$_5$O$_3$}}{128.17 \text{ g KC$_3$H_$_5$O$_3$}} \cdot \frac{1000\text{ mL}}{1\text{ L}} \\ \\ &= 0.234\text{ M}\end{aligned}

By solubility rules, potassium is completely soluble, so the compound will dissociate completely into potassium and lactate ions. Therefore, [KC₃H₅O₃] = [C₃H₅O₃⁺]. Note that lactate is the conjugate base of lactic acid.

Recall the Henderson-Hasselbalch equation:

\displaystyle \begin{aligned}\text{pH} = \text{p}K_a + \log \frac{\left[\text{Base}\right]}{\left[\text{Acid}\right]} \end{aligned}

[Base] = 0.234 M and [Acid] = 0.500 M. We are given that the resulting pH is 3.526. Substitute and solve for p<em>Kₐ</em>:

\displaystyle \begin{aligned} (3.526) & = \text{p}K_a + \log \frac{(0.234)}{(0.500)} \\ \\ 3.526 & = \text{p}K_a + (-0.330) \\ \\ \text{p}K_a & = 3.856\end{aligned}

In conclusion, the p<em>Kₐ </em>value of lactic acid is about 3.856.

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1 year ago
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Explanation:

7 0
3 years ago
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According to table g, which substance forms an unsaturated solution when 80. grams of the substance are stirred into 100. grams
e-lub [12.9K]

A saturated solution is one in which no more solute is able to dissolve in a given solvent at a particular temperature. Some amount of the solute is left undissolved in the solution.

Unsaturated solution has solute in lower proportions than required to form a saturated solution.

Supersaturated solution has solute in amounts greater than a saturated solution.

We can take the help of solubility curve in order to find out the amount of a salt required to prepare a saturated solution of that salt at a particular temperature.

The solubility of KI at 10^{0}C is 136 g/ 100 mL water

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So the correct answer will be KI, as it would need 136 g KI / 100 mL water to form a saturated solution at 10^{0}C.So, if we have 80g KI/ 100mL water it would be an unsaturated solution.

4 0
3 years ago
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tamaranim1 [39]

Initial concentration of magnesium nitrate M1 = 2.13 M

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Formula to use:

M1*V1 = M2*V2

V2 = M1*V1/M2

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Thus, the final volume of magnesium nitrate solution upon dilution is 1.65 L

7 0
3 years ago
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