Answer:
x = 14
Step-by-step explanation:
Extend line AB so that it intersects ray CE at point G. Then angles BGC and BAD are "alternate interior angles", hence congruent.
The angle at B is exterior to triangle BCG, and is equal to the sum of the interior angles at C and G:
138 = (376 -23x) +(x^2 -8x)
Subtracting 138 and collecting terms we have ...
x^2 -31x +238 = 0
For your calculator, a=1, b=-31, c=238.
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<em>Additional comment</em>
You will find that the solutions to this are x = {14, 17}. You will also find that angle BCE will have corresponding values of 54° and -15°. That is, the solution x=17 is "extraneous." It is a solution to the equation, but not to the problem.
For x=14, the marked angles are A = 84°, C = 54°.
Answer:
the students that brought a lunch box is 28
Step-by-step explanation:
The computation of the students that brought a lunch box is shown below:
= Entire school students × students that carry a lunch box ÷ entering students
= 84 students × 8 ÷ 24 students
= 28 students
Hence, the students that brought a lunch box is 28
Answer:
x = 35°
Step-by-step explanation:
These are corresponding angles. When a transversal crosses 2 parallel lines, 4 angles are created at each intersection, and each pair of corresponding angles between those are congruent.
These angles are congruent, so you can set them equal to each other:

Then, just solve for x:

You can check that by plugging it back into both:

Answer:
The correct option is D. 2/7
Step-by-step explanation:
Consider the provided information.
There are 8 volunteers including Andrew and Karen, 4 people are to be selected at random to organize a charity event.
We need to determine the probability Andrew will be among the 4 volunteers selected and Karen will not.
We want to select Andrew and 3 others but not Karen in the group.
Thus, the number of ways to select 3 member out of 8-2=6
(We subtract 2 from 8 because Andrew is already selected and we don't want Karen to be selected, so subtract 2 from 8.)
The required probability is:

Hence, the correct option is D. 2/7