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denis-greek [22]
2 years ago
14

Solve for . 5w-26=-4(w-7) Simplify your answer as much as possible. PLZ HELP

Mathematics
1 answer:
NikAS [45]2 years ago
7 0

Answer:

w = 6

Step-by-step explanation:

5w-26 = - 4 (w - 7)   multiply -4 through

5w - 26 = - 4w + 28  add 4w to each side to cancel it out on the right

5w + 4w - 26 = 28  

9w - 26 = 28  Now add 26 to each side

9w - 26 + 26 = 28 + 26

9w = 54   Now divide each side by 9

(9w)/9 = 54/9

w = 6

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The function f(x)=/-x is shown on the graph
Katyanochek1 [597]

we know that

For the function shown on the graph

The domain is the interval--------> (-∞,0]

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Statements

<u>case A)</u> The range of the graph is all real numbers less than or equal to 0

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8 0
2 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

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Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

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It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

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P( 80

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P( x < 80 ) = P( z

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P( 70

F) More than 130

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8,902 to the nearest thousand
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Answer:

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