Answer:
start at -18 degrees
To get to 15 it would be 33 degrees increased
1 min = 11 minutes
3 degrees = 33 degrees
You would have to wait 11 minutes
<u>Given</u>:
The box plots show daily low temperatures for a sample of days in two different towns.
We need to determine the most appropriate comparison of the spreads.
<u>Interquartile range of town A:</u>
The interquartile range can be determined by subtracting the end values of the boxes.
Thus, we have;
Interquartile range = 40 - 20
Interquartile range = 20
Thus, the interquartile range for town A is 20.
<u>Interquartile range for town B:</u>
The interquartile range for town B is given by
Interquartile range = 45 - 35
Interquartile range = 10
Thus, the interquartile range for town B is 10.
Hence, the interquartile range (IQR) for town A, 20° is greater than the IQR for town B, 10°
Hence, Option A is the correct answer.
Answer:
$6,400.00
Step-by-step explanation:
Following the rule of PEMDAS,
exponents go first in this scenario.
10^7 = 10000000
2.56*10000000 = 25600000
Then, divide the amount of money by the number of employees.
25600000/4,000 = 6400
Each employee would receive $6,400.00
Answer:
Step-by-step explanation: This is a question under linear regression analysis.
The question is trying to relate sales (in $1000) and and advertising.
Both sales and advertising are variables and are connected by the equation
Y = 32x + 8
Which is a linear regression equation of 2 variables.
Where x is the independent variable which represents advertising in this case and Y is the dependent variable which represents sales.
At $1 of adverts, we have $40 of sales.
We just simply put the fact that x = $1 (advertising) into the linear regression equation, we have the value of Y ( sales)
Y = 32(1) + 8
Y = 32 + 8
Y = $40.
Answer:
The correct answer is A.
To find the y-intercept, substitute in 0 for x and solve for y
.