Question

Triangle VDG- triangle VNQ What is the value of x? Enter your answer in the box.

Answer 1

Answer:

its 8

Step-by-step explanation:

Answer 2

Question:

The image of the question is attached below.

Answer:

x = 40

Solution:

Given ΔVDG $\sim$ ΔVNG.

DG = 207, NQ = 138, GQ = 60, QV = x

In two triangles are similar, then the measures of the corresponding sides are in proportional to each other.

$\Rightarrow\frac{DG}{NQ}=\frac{GQ}{QV}$

$\Rightarrow\frac{207}{138}=\frac{60}{x}$

Do cross multiplication, we get

$\Rightarrow{207\times x}=138\times60$

$\Rightarrow{207\times x}=8280$

$\Rightarrow{207x}=8280$

Divide by 207 on both sides of the equation, we get

$\Rightarrow\frac{{207x}}{207} =\frac{8280}{207}$

$\Rightarrow x =\frac{8280}{207}$

⇒ x = 40

⇒ QV = 40

Hence the value of x is 40.