Question

Which set of numbers is correctly ordered from greatest to least?

Answer 1

Answer:

Step-by-step explanation:

Given numbers: $7\tfrac{1}{3}\,,\,\frac{221}{30}\,,\,7.\overline{36}\,,\,16\sqrt{2e}$

We need to arrange these numbers from greatest to least .

On writing these numbers in simplified form, we get

$7\tfrac{1}{3}=\frac{22}{3}=7.33\\\frac{221}{30}=7.367\\7.\overline{36}=7.3636...\\16\sqrt{2e}=16\times \sqrt{5.437}=16\times 2.332=37.312$

Here,$7.\overline{36}$ has a non-terminating repeating decimal expansion .

Vale of e = 2.718$16\sqrt{2e}\,,\,\frac{221}{30}\,,\,7.\overline{36}\,,\,7\tfrac{1}{3}$

The greatest number is $16\sqrt{2e}$

Then number less than $16\sqrt{2e}$ is $\frac{221}{30}$

Then number less than $\frac{221}{30}$ is $7.\overline{36}$

Then number less than $7.\overline{36}$ is $7\tfrac{1}{3}$

i.e $16\sqrt{2e}\,,\,\frac{221}{30}\,,\,7.\overline{36}\,,\,7\tfrac{1}{3}$

So, answer is option 4.

Answer 2

Answer:

It's D.

Step-by-step explanation:

Convert each number to decimal format.

It is option D , if we convert as above we get

7.36799, 7.36666.., 7.363636.., 7.33333..