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4 years ago

SOMEBODY PLEASE HELP ME! IM BEGGING YOU! I MIGHT FAIL ALGEBRA 1 AND HAVE TO REDO 8TH GRADE!! PLEASE JUST HELP ME!!!

Mathematics

1 answer:

Misha Larkins [42]4 years ago

5 0

5x^2+6=f(x)

and your graph plug that equation into an graph creator and it will automaticlly make your graph

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Solve using the percent proportion.

Ray Of Light [21]

Answer:

20 of 80 = 16

25 of 75 = 18.75

90 of 180 = 162

75 of 90 = 67.5

120 of 1500 = 1800

45 of 90 = 40.5

50 of 120 = 60

35 of 78 =27.3

40 of 90 = 36

25 of 150 = 37.5

hope it helps

7 0

3 years ago

[Slope & Rate of Change]: What is the slope of this line?

ankoles [38]

<span>Notice that this slope will be the same if the points (1,3) and (2, 5) are used for the calculations. For straight lines, the rate of change (slope) is constant (always the same). For every one unit that is moved on the x-axis, two units are moved on the y-axis. This is true at any location on the line.</span>

3 0

4 years ago

Read 2 more answers

What is the midpoint of EF If E has the coordinates of (2,4) and F has coordinates of (6,8)

allsm [11]

Answer:

$\boxed {\boxed {\sf (4,6) }}$

Step-by-step explanation:

The midpoint formula is:

$(\frac{{x}_{1}+{x}_{2}}{2},\frac{{y}_{1}+{y}_{2}}{2} )$

where (x₁, y₁) and (x₂, y₂) are the points are the endpoints.

We are given the points: (2,4) and (6,8). Therefore,

$x_1=2\\y_1=4 \\x_2=6 \\y_2=8$

Substitute the values into the formula.

$(\frac{2+6}{2},\frac{4+8}{2})$

Find the x coordinate first.

Add 2 and 6: 2+6=8
Divide by 2: 8/2=4

$(4, \frac{4+8}{2})$

Find the y-coordinate next.

Add 4 and 8: 4+8= 12
Divide by 2: 12/2=6

$(4,6)$

The midpoint of EF is (4,6)

4 0

3 years ago

Read 2 more answers

Suppose you flip a fair coin N times. Let random variable h be the number of heads that occur. Use the normal approximation to e

Mariana [72]

Answer:

If n = 1000000, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If n = 10400, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If N = 102, then

$P(h < 40 or h > 60) = 1-P(40$

Step-by-step explanation:

Since the coin is fair, then the probability that a filp is heads is 1/2. Given N tries, the amount of heads can be approximated with a Normal distribution with mean μ = N *1/2 = N/2 and standard deviation σ = √(N*1/2 * 1/2) = √N/ 2

The density function of that random variable is given by de following formula

$f_X(k) = \frac{1}{\sqrt{2\pi} * \sigma} e^{\frac{-(k-\mu)^2}{2\sigma^2} } = \frac{2}{\sqrt{2\pi N}} e^{\frac{-2(k-N/2)^2}{N} }$

If n = 1000000, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If n = 10400, then

$P(h E [495000, 505000]) = \int\limits^{50500}_{495000} {\frac{2}{\sqrt{2000000\pi}} e^{\frac{-(k-500000)^2}{500000} }} \, dk$

If N = 102, then

$P(h < 40 or h > 60) = 1-P(40$

4 0

3 years ago

Which value of p is a solution to this inequality: 10p - 8 2 12?

jolli1 [7]

Answer: d

Step-by-step explanation:

7 0

3 years ago