The approximate area of each half of △ACB is 28 square feet
<h3>Area of a triangle</h3>
The formula for calculating the area of a triangle is expressed as:
A = 0.5absintheta
Given the following
PB =11ft
<PCB = 65degrees
Using the SOH CAH TOA identity
tan<PCB = 11/CP
CP = 11/tan65
CP = 5.13 ft
Determine the required area
Area = 0.5(11)(5.13)sin90
Area = 5.5 * 5.13
Area . = 28 square ft
Hence the approximate area of each half of △ACB is 28 square feet
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The answer is D.
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1/2
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2/5 = 4/10
4/10 + 1/10 = 5/10
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it's G)
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40/3
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