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Flura [38]
3 years ago
9

The perimeter of a rectangle is 200 meters. If the width is 25% of the length, find the dimensions of the rectangle

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

The rectangle dimensions are 20 m by 80 m

Step-by-step explanation:

Let W represent the width and L the length.  Then W = 0.25L.

The perimeter, P, is 200 m.  The formula for that is P = 2W + 2L.

Substituting 0.25L for W, we get:

2(0.25L) + 2L = 200 m, or (after mult. both sides by 2):  L + 4L = 400 m

Then 5L = 400 m, and L = 80 m.  Thus, W = 0.25(80 m) = 20 m.

The rectangle dimensions are 20 m by 80 m

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<h3>3 Answers: Choice D, Choice E, Choice F</h3>

============================================================

Explanation:

The inequality 6x - 10y ≥ 9 solves to y ≤ (3/5)x - 9/10 when you isolate y.

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-----------

I'll show an example of something that doesn't work. Let's pick on point A.

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