Answer:
Below in bold.
Step-by-step explanation:
c) 3 x (9^2)^3/4 x ((81^3)^5/6
= 3 x 81^3/4 x 81^15/6
= 3 x 81^(3/4 + 15/6)
= 3 x 81^13/4
= 3 x 3^13
= 3^14
= 4,782,969.
f) (5x^-1y^2)^-2 / (25 x^2 y - 1)^2
= 5^-2 x^2y^-4 / 625 x^4y^-2
= 5^-2 x^-2 y^-2 / 5^4
= 5^-6 x^-2y^-2
= 0.000064x^-2y^-2.
Mean (Average) 48
Median 47.5
Range 66
Mode 72, appeared 2 times
Geometric Mean 41.680398411848
Largest 81
Smallest 15
Sum 480
Count 10
Answer:
a; she will have $8812
b: It will be enough for her trip
Step-by-step explanation:
In this question, we are tasked with calculating how much a certain value in a savings account that is earning an interest that is compounded annually will be worth.
To calculate this, we use the compound interest formula;
A = P(
Where A is the amount after that number of years which of course we want to calculate
P is the principal amount which is the amount we are investing which is $6439 according to the question
r is the interest rate which is 4% = 4/100 = 0.04
t is the time which is 8 years
n is 1 which is the number of times interest will be compounded annually
We plug these values as follows;
A = 6439(1 + 0.04/1)^8
A = 6439(1.04)^8
A = $8,812.22
This amount is greater then the needed $8,500 for the trip and of course it will be enough
-7x + 6y =5
x intercept. y=0
-7(x) + 6(0)=5
x=-5/7
y intercept, x=0
-7(0)+6(y) =5
y=5/6