Question

If a gas has a proportionality constant of 4.32 x 10-4 mol at room temperature for a particular solvent, what will the

Answer 1

$0.0467 X 10^{-4} M/kPa$ is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

What is Henry's law?

Mathematically, we can get this from Henry's law

From Henry law;

Concentration = Henry constant × partial pressure

Thus Henry constant = $\frac{Concentration}{partial \;pressure}$

Henry constant = $\frac{4.32 \;X \;10^{-4} mol}{92.4kPa}$

$= 0.0467 X 10^{-4} M/kPa$

Hence, $0.0467 X 10^{-4} M/kPa$ is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

Learn more about the Henry's law here:

brainly.com/question/16222358

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