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qaws [65]
2 years ago
9

If a gas has a proportionality constant of 4.32 x 10-4 mol at room temperature for a particular solvent, what will the

Chemistry
1 answer:
inysia [295]2 years ago
6 0

0.0467 X 10^{-4} M/kPa is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

<h3>What is Henry's law?</h3>

Mathematically, we can get this from Henry's law

From Henry law;

Concentration = Henry constant × partial pressure

Thus Henry constant = \frac{Concentration}{partial \;pressure}

Henry constant = \frac{4.32 \;X \;10^{-4} mol}{92.4kPa}

= 0.0467 X 10^{-4} M/kPa

Hence, 0.0467 X 10^{-4} M/kPa is the solubility of the gas when it exerts a partial pressure of 92.4kPa.

Learn more about the Henry's law here:

brainly.com/question/16222358

#SPJ1

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