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3 years ago

N2H4 (I)--> N2 (g) + 2 H2(g)

Chemistry

1 answer:

photoshop1234 [79]3 years ago

4 0

Answer:

65.25 grams of water

Explanation:

Moles of H2 = mass/ M.w

= 7.25g /2

=3.625 mol H2

Moles of H2O = moles of H2 = 3.625 mole

Mass of H2O = mol * molar wight

= 3.625 * 18 = 65.25 g H2O

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What is a dipeptide and a peptide bond?

Verdich [7]

A polypeptide is a peptide composed of two amino-acid and a peptide bond is a chemical bond formed between two molecules, when the carboxyl group of one molecule reacts with the amino group of the other molecule, releasing a molecule of water.

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3 years ago

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Excited lithium ions emit radiation at a wavelength of 670.8 nm in the visible range spectrum. Calculate the frequency of a phot

zzz [600]

Answer : The frequency of a photon of radiation is, $4.47\times 10^9s^{-1}$

Explanation : Given,

Wavelength of the radiation = 670.8 nm

First we have to convert wavelength form 'nm' to 'm'.

Conversion used : $(1nm=10^{-9}m)$

So, the wavelength of the radiation = 670.8 nm = $670.8\times 10^{-9}m$

Now we have to calculate the frequency of a photon of radiation.

Formula used : $\nu =\frac{c}{\lambda}$

where,

$\nu$ = frequency of a photon of radiation

$\lambda$ = wavelength of the radiation

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get the frequency of a photon of radiation.

$\nu =\frac{3\times 10^8m/s}{670.8\times 10^{-9}m}$

$\nu =4.47\times 10^9s^{-1}$

Therefore, the frequency of a photon of radiation is, $4.47\times 10^9s^{-1}$

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4 years ago

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you wish to prepare an hc2h3o2 buffer with a ph of 5.44. if the pka of the acid is 4.74, what ratio of c2h3o2-/hc2h3o2 must you

vazorg [7]

The ratio of buffer C₂H₃O₂ /HC₂H₃O₂ must you use are1:0.199 or 10:2

the ratio of buffer C₂H₃O₂ /HC₂H₃O₂ can be calculate using the Henderson-Hasselbalch Equation which relates the pH to the measure of acidity pKa. The equation is given as:

pH = pKa + log ([base]/[acid]

Where,

[base] = concentration of C₂H₃O₂in molarity or moles

[acid] = concentration of HC₂H₃O₂ in molarity or moles

For the sake of easy calculation, allow us to assume that:

[base] =1

[acid] = x

Therefore using equation 1,

5.44 = 4.74 + log (1 / x)

log [base / acid] = 0.7

1 / x = 5.0118

x = 0.199

The required ratio of buffer C₂H₃O₂ /HC₂H₃O₂ is 1:0.199 or 10:2

learn more about buffer ratio here brainly.com/question/4342532

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1 year ago

What are intermediates in a reaction? Give an example.

Andrews [41]

In a reaction, molecular entity that is formed from the reactants. For example, consider this hypothetical stepwise reaction: A + B → C + D.

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3 years ago

A sample of a pure compound that weighs 60.3 g contains 20.7 g Sb (antimony) and 39.6 g F (fluorine). What is the percent compos

Volgvan

Answer:

The percent composition of fluorine is 65.67%

Explanation:

Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.

That is, the percentage composition is the percentage by mass of each of the elements present in a compound.

The calculation of the percentage composition of an element is made by:

$percent composition element A=\frac{total mass of element A}{mass of compound} *100$

In this case, the percent composition of fluorine is:

$percent composition of fluorine=\frac{39.6 g}{60.3 g} *100$

percent composition of fluorine= 65.67%

<u><em>The percent composition of fluorine is 65.67%</em></u>

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4 years ago