Answer:
Given expression: 6(2b-4). To find the value of 6(2b-4) at b= 5, we need to substitute the b=5 in the expression, we get….Therefore, the value of 6(2b-4) is 36, when b=5.
Explanation:
Given expression: 6(2b-4). To find the value of 6(2b-4) at b= 5, we need to substitute the b=5 in the expression, we get….Therefore, the value of 6(2b-4) is 36, when b=5.
1 mol of formic acid is correct. There are two oxygen atoms in formic acid, compared to just one for the other molecules.
Since monosaccharides are the simplest units of carbohydrates, then they are made up of carbon, hydrogen, and oxygen atoms.
empirical formula : CxH2xOx
where

Monosaccharides can be classified by the number x of carbon atoms they contain: triose(3) tetrose (4), pentose (5), hexose (6), heptose (7), and so on.
Answer:
156.86 g / mol
Explanation:
We start from the molarity law
Cm = n / V
n = w / M
then
Cm = (w / M) / V
Cm = w / (M × V)
where:
Cm is the molarity
n number of moles
w a mass of the solute
M is the molar mass of the solute (which is needed)
V the volume of the solution in liters
Then the M can be calculated as following:
M = w / (Cm × V)
M = 100 / (0.75 × 0.85) = 156.86 g / mol