Answer:
There are two factors that can affect electron affinity. These are atomic size and nuclear charge. ... The smaller the atom is, the closer the outermost shell is; therefore, it is a stronger attraction between the nucleus and the incoming electron. That means the electron affinity is higher for smaller atoms.
Explanation:
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Answer:
C3H6O
Explanation:
Data obtained from the question. This includes:
Carbon (C) = 0.62069 g
Hydrogen (H) = 0.103448 g
Oxygen (O) = 0.275862 g
The empirical formula can be obtained as follow:
Step 1:
Divide by their molar mass.
C = 0.62069 / 12 = 0.0517
H = 0.103448 / 1 = 0.103448
O = 0.275862 / 16 = 0.0172
Step 2:
Divide by the smallest number.
C = 0.0517 / 0.0172 = 3
H = 0.103448 / 0.0172 = 6
O = 0.0172 / 0.0172 = 1
Step 3:
Writing the empirical formula.
The empirical formula is C3H6O
The correct answer is approximately 1.95g. First, take (1.022*10^10)/(1.277*10^9). This is the same as time elapsed/half-life. This gives you 8, which is the number of half lives. Then multiply mass (500.3g) by (1/2)^8, resulting in 1.95g, which is the answer.
Answer:
a. ΔH⁸ = -1420 kJ/mol b. ΔH⁸ = -1144.84 kJ/mol
Explanation:
a.
C₂H₄ (g) + 3 O₂ (g) ------------------------ 4 CO₂ (g) + 2 H₂O (l) ΔH⁸ = ?
ΔH⁸f kJmol 52.47 0 -399.5 -285.83
ΔH⁸ = 2(-399.5) + 2 (-285.83) - (52.47)
ΔH⁸ = -1420 kJ/mol
b.
H₂S (g) + 3 O₂ (g) ---------------------- 2 H₂O (l) + 2 SO₂ (g)
ΔH⁸f kJmol -20.50 0 -285.83 -296.84
ΔH⁸ = 2(-285.83) + 2 (-296.84) - (-20.50)
ΔH⁸ = -1144.84 kJ/mol
