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3 years ago

What is the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81?

Mathematics

1 answer:

Marizza181 [45]3 years ago

6 0

Answer: d. 1.3333

Step-by-step explanation:

We know that the standard error of a sampling distribution is given by :-

$S.E.=\dfrac{\sigma}{\sqrt{n}}$

, where $\sigma$ = Population standard deviation.

n= Sample size.

AS per given , we have

$\sigma =12$

n=81

Then, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 will be :-

$S.E.=\dfrac{12}{\sqrt{81}}$

$=\dfrac{12}{\sqrt{9^2}}=\dfrac{12}{9}\\\\=\dfrac{4}{3}\\\\\approx1.3333$

Hence, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 is 1.3333.

Thus the correct answer is d. 1.3333 .

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3 years ago

A person that weighs 179 lbs needs an IV Drip in mL. The drug only comes in powder form but can be converted as 10 mg is equal t

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Solution:

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As given person needs IV Drip in m L.

Also,→ 10 mg = 2 m L

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Also, 10 mg → 2 m L

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3 years ago

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kykrilka [37]

Answer:

1 5/12

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2 years ago

Is the product of two irrational numbers always gonna be irrational

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3 years ago

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Solving for x:

$\begin{gathered} 3x+55-55=85-55 \\ 3x=30 \\ \frac{3x}{3}=\frac{30}{3} \\ x=10 \end{gathered}$

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