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2 years ago

25+ POINTS PLEASE HELP!!!!!!!!!! ||| NEED ASAP

Biology

1 answer:

Kay [80]2 years ago

7 0

Explanation:

Issun Sengeki... Messatsu!

Here's the sentence:

If the light bulbs often burn out, then I can use a different method. The resolution could be using a parallel circuit. The reason being is because a parallel circuit will have to available ways to transfer power, so if one route fails, the other prevails!

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Biotic factors cannot live without abiotic factors. True False

sergeinik [125]

Depends, if the biotic factor is a chipmunk or something of that case, its natural habitat is a rock, which is biotic. but...if the animal is something like a deer they don't need abiotic factors. its your chose to chose but I'm leaning more twords false because not ALL biotic factors cant go without an abiotic factor

7 0

3 years ago

The carrying capacity for a species in an ecosystem is primarily determined by

coldgirl [10]

The carrying capacity for a species in an ecosystem is primarily determined by the resources in the ecosystem.

Explanation:

The availability of food, raw materials, water and other resources in that ecosystem are those factors that is used for the determination of the carrying capacity. The factors such as nature, the levels of wastage accumulation, removal of very important things from the system also determines the carrying capacity. a system's carrying capacity may involve matters such as available supplies of food, water, raw materials, and/or other similar resources.

The main components that determines the carrying capacity of an ecosystem are food and other resources, provided, the humans must not disturb the ecosystem for their self survival. The resources limitations and their availability determines this factor to a greater extent.

6 0

2 years ago

What is the major function of a leaf

ANEK [815]

Answer:

Photosynthesis

Explanation:

The leaf (from Latin fŏlĭum, fŏlĭi) is the vegetative and generally flattened organ of vascular plants, specialized mainly to perform photosynthesis. The morphology and anatomy of stems and leaves are closely related and, together, both organs constitute the stem of the plant.

Typical leaves - also called nomophiles - are not the only ones that develop during the life cycle of a plant. From the germination, different types of leaves follow each other - coiled, primordial leaves, prophilic, bracts and antophiles in flowers - with very different forms and functions.

A nomophile usually consists of a flattened sheet, a short stem - the petiole - that joins the sheet to the stem and, at its base, a pair of appendages - the stipules. The presence or absence of these elements and the extreme diversity of forms of each of them has generated a rich vocabulary to categorize the multiplicity of types of leaves presented by vascular plants, whose description is called foliar morphology.

5 0

3 years ago

Read 2 more answers

Many bacteria do not interact with humans, but those that do can always be classified as either harmful or not harmful to humans

Burka [1]

The answer is letter B.

Some bacteria that interact with humans can cause benefits to the body when they are small in numbers. An example of this bacteria is the lactobacilli which can be found as an ingredient in some drinks that can purify the digestive system. Though, they can only be taken in small amounts because they may overwhelm the immune system which can cause major complications within the internal organs. Some bacteria that interact with humans can be harmful because of their capacity to divide at a fast rate.

4 0

3 years ago

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny pl

nalin [4]

Here is the complete question

The seeds in bush bean pods are each the product of an independent fertilization event. Green seed color is dominant to white seed color in bush beans.

If a heterozygous plant with green seeds self-fertilizes, what is the probability that 6 seeds in a single pod of the progeny plant will consist of:

A) 4 green and 2 white seeds?

B) all white seeds?

C) at least 5 white seeds?

Answer:

A) 0.3

B) 0.0002

C) 0.001

Explanation:

Let the allele for Green plant be = P

Let the allele for white plant be = p

Let the heterozygous plant be Pp, if self fertilization occurs we have:

P p

P PP Pp

p Pp pp

From the punnet square above, we have the following cross;

PP, Pp, Pp, pp

Since P is dominant to p; we have a phenotypic ratio of 3:1 between the dominant phenotype ( PP, Pp, Pp ) and recessive phenotype ( pp )

NOW, the probability for the green plant(i.e PP or Pp) will be: $Pr(G)=\frac{3}{4}$

the probability for the white plant (pp) will be: $Pr (W)= \frac{1}{4}$

what is the probability that 6 seeds in a single pod of the progeny plant will consist of 4 green and 2 white seeds?

$Pr(4G2W)$ = $(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

The probability includes the use of permutation:

$Permutation(P)=\frac{6!}{(4!*2!)} * (\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

= $15*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{3}{4})*(\frac{1}{4})*(\frac{1}{4})$

= 0.2966

≅ 0.3

What is the probability that 6 seeds in a single pod of the progeny plant will consist of all white seeds?

Since probability for white seed = $\frac{1}{4}$

The probability that 6 seeds will consist of all white seeds will be = $(\frac{1}{4})^6$

= 2.44 × 10⁻⁴

= 0.000244

≅ 0.0002

What is the probability that 6 seeds in a single pod of the progeny plant will consist of at least 5 white seeds?

For at least 5 white seeds, the probability will consist of 5 white seeds and 6 white seeds.

For 5 white seeds; we have:

5 White and 1 Green Since there are 6 permutations.

The probability For 5 white seeds will therefore be :

$Pr(5 seeds)=(\frac{1}{4})^5*(\frac{3}{4})^1 *6$

= 7.32 × 10⁻⁴

= 0.000732

For 6 white seeds; we have:

Only one permutation for 6 whites since there will no be any presence of any green seed.

$Pr(6seeds)=(\frac{1}{4})^6$

= 2.44 × 10⁻⁴

= 0.000244

∴

The total probability for at least 5 white seeds = 0.000732 + 0.000244

= 9.76 × 10⁻⁴

= 0.000976

≅ 0.001

3 0

3 years ago