Sol. 1) Prime factors of 12 = 2 x 2 x 3 Prime factors of 15 = 3 x 5 Prime factors of 21 = 3 x 7
So, HCF (Product of all common factors of given three numbers 12, 15 and 21)=3 and LCM of 12, 15 and 21 = Product of common factors with other remaining factors i.e., LCM = 3 x 22 x 5 x 7 = 420
2) Prime factors of 17 = 17 x 1 Prime factors of 23 = 23 x 1 Prime factors of 29 = 29 x 1 So, HCF of 17, 23 and 29 = 1 and their LCM = 17 x 23 x 29 = 11339
3) Prime factors of 8 = 2 x 2 x 2 Prime factors of 9 = 3 x 3 Prime factors of 25 = 5 x 5
So, HCF of 8, 9 and 25 is 1 because their is no common factors in the prime factorization of 8, 9 and 25.
