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Tju [1.3M]
4 years ago
5

Lines v and what are parallel. Which statement can you NOT deduce from this information

Mathematics
1 answer:
nikdorinn [45]4 years ago
6 0
You cannot deduce the length of the lines 
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Can any one help me on this? Please thank you
nignag [31]
The area of a triangle is base length x height then divide all by 2, 
so 12 x 10 /2
=60 ft²
5 0
3 years ago
Which is bigger:<br> 3/8 or 0.38.<br> Can you tell me how to work it out?please!
Usimov [2.4K]
You do 3 x 8 / 100 to work out 3/8 as a decimal. So its 0.24. 0.38 is bigger
7 0
3 years ago
X/x^2-16-7/x^2+5x+4  simplify
Lana71 [14]
<u>5x³ - 12x² + -7</u>
         x²
Simplified answer.
4 0
3 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =
geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

L_z=9-\lambda=0

L_\lambda=x-y+z-1=0

L_\mu=x^2+y^2-1=0

L_z=0 tells us \lambda=9, so that

L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu

L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}

Then with L_\mu=0, we get

x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2

and L_\lambda=0 tells us

x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}

Then there are two critical points, \left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right). The critical point with the negative x-coordinates gives the maximum value, 9+\sqrt{185}.

8 0
4 years ago
Please help I’m so close to passing math
kirill115 [55]

Answer:

$0.14 per ounce of salsa

Step-by-step explanation:

2.80/20

Move decimal to make the number a whole number

(Have to move the decimal the same amount of spaces)

28/200

0.14

Hope this helps. Have a nice day

8 0
3 years ago
Read 2 more answers
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