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2 years ago

15

How many tenths greater is the 2 in the thousands place than the 2 in the trnths place in 2,453.29

1 answer:

RoseWind [281]2 years ago

6 0

The answer is 0.100 Tenths

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What is 5 1/4 divided by 7?

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ANSWER: I think it’s 3/4

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3 years ago

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CAN SOMEBODY HELP ME PLEASE

Mashutka [201]

Answer:

The answer to your questions are:

15.- 45 mg

16.- 25 kg

17.- 185 pounds

18.- 6 mg

Step-by-step explanation:

D = (a M) / (a + 12)

15.-

a = 4 years

M = 180

D = (4 x 180) / (4 + 12) = 720 / 16

D = 45 mg

16.- 1 pound --------------- 0.4535 kg

55 pounds ------------ x

x = 55 x 0.4535 / 1

x = 24.94 ≈25 kg

17.- 1 pound --------------- 0.4535 kg

x --------------- 84.09 kg

x = 84.09x 1 /0.4535

x = 185.42 pounds

18.- M = 18 mg what is 1/3 of the adult dose?

M = 18/3 = 6 mg

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Factor x^2a^2 + 3xa^2 + 2a^2. Show your work.

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$x^2a^2 + 3xa^2 + 2a^2= \\ a^2(x^2+3x+2)= \\a^2(x^2+2x +x+2)= \\a^2(x(x+2)+(x+2))= \\a^2(x+2)(x+1)$

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3 years ago

Need help on these trig homework

allochka39001 [22]

8. The length of the support is 7. 9 m

9. The length of the conveyer is 12m

3. a = 59m

A = 44°

B = 52°

4. c = 88. 6 mm

b = 49. 1 m

B = 34°

<h3>How to solve the trigonometry</h3>

8. We have the angle to be 20 degrees

Opposite side = x

hypotenuse = 23m

Using the sine ratio

sin θ = opposite/ hypotenuse

$sin 20 = \frac{x}{23}$

Cross multiply

$sin 20$ × $23 = x$

$x = 0. 3420$ × $23$

x = 7. 9 m

The length of the support is 7. 9 m

9. The angle of elevation is 37. 3 degrees

Hypotenuse = 19 . 0m

Opposite = x

Using the sine ratio

sin θ = opposite/ hypotenuse

$sin 37. 3 = \frac{x}{19}$

cross multiply

$x = 0. 6059$ × $19$

x = 11.5

x = 12 m in 2 significant figures

The length of the conveyer is 12m

3. To determine the sides and angles, we use the sine rule;

$\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}$

For side a, we use the Pythagorean theorem

$c^2 = a^2 + b^2$

$85^2 = a^2 + 67^2$

$a = \sqrt{89^2-67^2}$

$a = \sqrt{3432}$

a = 58. 58, a = 59m

To find angle A and B, use the sine rule

$\frac{59}{sin A } = \frac{85}{sin 90}$

cross multiply

$sin A$ × $85$ = $sin 90$ × $59$

make sin A subject of formula

$sin A = \frac{59}{85}$

$sin A = 0. 6941$

A = $sin^-^1(0. 6941)$

A = 44°

$\frac{67}{sin B} = \frac{85}{sin 90}$

cross multiply

$sin B$ × $85$ = $sin 90$ × $67$

make sin b subject of formula

$sin B = \frac{67}{85}$

$sin B = 0. 7882$

B = $sin^-^1( 0. 7882)$

B = 52°

4. To find the sides, we use the sine rule;

$\frac{74. 0}{sin 56. 6} = \frac{c}{sin 90}$

Cross multiply

$sin 56. 6$ × $c = sin 90$ × $74$

make 'c' subject of formula

$c = \frac{74}{0. 8348}$

c = 88. 6 mm

To find length b, we use the Pythagorean theorem

$c^2 = a^2 + b^2$

$b^2 = c^2 - a^2$

$b^2 = 88. 8^2 - 74^2$

$b = \sqrt{7885. 44 - 5476}\\\\ b = \sqrt{2409. 44}$

b = 49. 1 m

$\frac{74. 0}{sin 56. 6} = \frac{49. 1}{sin B}$

cross multiply

$sin B = \frac{40. 99}{74. 0}$

B = $sin^-^1(0. 5539)$

B = 34°

Learn more about trigonometric identity here:

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1 year ago

Renee is wanting to join a gym.

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Pumping iron: 10x+90=0
Fit for life: 15x+50=0

Set them equal to each other. 10x+90=15x+50. Solve for x. Subtract 50 from both sides, get 10x+40=15x, then subtract 10x from both sides, getting 40=5x. Divide 5 from both sides to isolate x, x=8. After 8 months the two gyms will cost the same.

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3 years ago