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AlladinOne [14]
3 years ago
12

There are_____in the listening process

Mathematics
2 answers:
valentina_108 [34]3 years ago
6 0

Answer:

5 steps.

Step-by-step explanation:

  • Recieving
  • Understanding
  • Evaluating
  • Remembering
  • Responding

hope it helps!

Jobisdone [24]3 years ago
6 0
They’re is 5 steps in the listening progress!
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Help please
Vesnalui [34]
A = 1/4   (0.25)
B = 7/16 (0.4375)
C = 5/8 (0.625)
D = 3/4 (.75)

the last option is your answer
5 0
3 years ago
Ricky has 600 apples if Ricky gives 200 apples away. How many apples dose he have left. A: 500 B: 600 C: 400 D: 8,000
luda_lava [24]

Answer:

C. 400

Step-by-step explanation:

Subtract 600 by 200, and get your answer.

8 0
3 years ago
Read 2 more answers
My number is the first multiple of 3,6, and 9 what is my number
Paladinen [302]

Answer:

18 is the first multiple of 3,6, and 9.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Complete the square to write each ellipse in standard form. x^2 + 4y^2 + 24y = 32​
Alexus [3.1K]

Answer: Okay, the answer is x^2/68+(y+3)^2/17=1.

Step-by-step explanation: Step. 1 Complete the square for 4y^2+24y: 4(y+3)^2−36.

Step 2. You’ll need to substitute 4(y+3)^2−36 for 4y^2+24y in the equation x^2+4y^2+24y=32: x^2+4(y+3)^2–36=32.

Step 3. So you’ll need to move –36 to the right side of the equation by adding 36 to the both sides: x^2+4(y+3)^2=32+36.

Step 4 You add 32 and 36: x^2+4(y+3)^2=68.

Step 5. You divide each term by 68 to make the right side equal to one: x^2/68+4(y+3)^2/68=68/68.

And step 6. You’ll need to simplify each term in the equation in order to set the right side equal to 1. The standard form of an ellipse or hyperbola requires the right side of the equation be 1: x^2/68+(y+3)^2/17=1. I hope you download Math-way app to calculate this ellipse in standard form to be extremely helpful, please mark me as brainliest, and have a great weekend! :D

6 0
3 years ago
The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
velikii [3]

By subtracting the given addend to the sum, we see that the other addend is:

6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 - 8

<h3>How to get the other addend?</h3>

We know that the sum of two polynomials is:

8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9

One of the addends is:

2d^5 - c^3d^2 + 8cd^4 + 1

To get the other addend, we can subtract the given addend to the sum:

8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9 - (2d^5 - c^3d^2 + 8cd^4 + 1)\\\\6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 - 8

Then we can conclude that the other addend is:

6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 - 8

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

4 0
2 years ago
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