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AlladinOne [14]
3 years ago
12

There are_____in the listening process

Mathematics
2 answers:
valentina_108 [34]3 years ago
6 0

Answer:

5 steps.

Step-by-step explanation:

  • Recieving
  • Understanding
  • Evaluating
  • Remembering
  • Responding

hope it helps!

Jobisdone [24]3 years ago
6 0
They’re is 5 steps in the listening progress!
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X – y +z = 5<br> x + y + 2z = 19<br> x + y + z = 15
otez555 [7]

Answer:

x=5,y=5,z=5

Step-by-step explanation:

x=15-y-z

15-y-z-y+z=5

15-2y=5

y=5

x+y+z=15

15-2y+y+z=15

15-10+5+z=15

z=5

x-y+z=5

x-5+5=5

x=5

8 0
3 years ago
From a balloon 760 feet high, the angle of depression to the ranger headquarters is 89°18'. How far is the headquarters from a p
Gnom [1K]

Answer:

9 ft

Step-by-step explanation:

let x be the required  distance.

\frac{760}{x} =tan~ 89^\circ18 '\\x=\frac{760}{tan~89^\circ 18' } =\frac{760}{tan~89 \frac{18}{60}} =\frac{760}{tan~89.3^\circ} \\or~x \approx 9~ft

6 0
3 years ago
Given the following system of equations:
Artemon [7]

Answer: Divide the first equation, −4x + 8y = 16, by 2

Step-by-step explanation:

3 0
3 years ago
Planners of an experiment are evaluating the design of a sphere of radius r that is to be filled with helium (0°c, 1 atm pressur
Vikentia [17]
The solution is:A mole of gas occupies 22.4 L A liter is 1000 cubic centimeters because 1 cubic centimeter = 1 mL
One Helium molecule (essentially one helium atom) has atomic mass 4 g/mol So for every 22400 cubic centimeters of volume, we have 4 grams of helium Density of helium = 4g / 22400 cm^3 = 1g / 5600 cm^3 
Volume of a sphere = (4/3)(pi)r^3 Volume of the outside sphere (the entire sphere) is (4/3)(pi)(R+T)^3 Volume of the inside sphere (the hollow region) is (4/3)(pi)R^3 
The difference for the volume of silver. (4/3)(pi)(R+T)^3 - (4/3)(pi)R^3 = (4/3)(pi)(3R^2T + 3RT^2 + T^3) 
The density of silver is 10.5g/cm^3 
So the mass of the silver is computed by:10.5*(4/3)(pi)(3R^2T + 3RT^2 + T^3) = (14*pi)(3R^2T + 3RT^2 + T^3) = (14pi)T(3R^2 + 3RT + T^2) 

Now for the mass of helium: volume x density = (4/3)(pi)R^3 (1/5600) = (pi/4200)R^3 

Set the two masses equal: (pi/4200)R^3 = (14pi)T(3R^2 + 3RT + T^2) R^3 = 58800*T(3R^2 + 3RT + T^2) R / T = 58800*(3R^2 + 3RT + T^2) / R^2 = 58800*( 3+T/R^2+(T/R)^2) 
then solve for xx = T / R 1/x = 58800*( 3+x/R+x^2) 1/58800 = x (3 + x/R + x^2) 1/58800 = 3x + x^3 x^3 + 3x - 1/58800= 0 x = ~ 5.66893x10^(-6)
6 0
3 years ago
Two way table’s , bar graphs and segmented bar graphs are useful for displaying what kind of data?why?
NeX [460]

Step-by-step explanation:

Statisticians use two-way tables and segmented bar charts to examine the relationship between two categorical variables.

5 0
2 years ago
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