<span>it depends how the interest is calculated, but there's not much of a difference
assuming its continuously compouned, you use this formula: A(t)=Pe^(rt), where A is the final amount, P is the initial investment, r is the interest, and t is the time in years
you want to find t such that A(t)=18,600 so 18,600=1000e^(.0675t)
you need to use logarithm to figure it out, take the natural log of both sides
the following properties will come into use:
ln(a*b)=ln(a)+ln(b)
ln(a^b)=bln(a)
ln(e)=1
taking the natural log
ln(18,600)=ln(1000e^(.0675t))
ln(18,600)=ln(1000)+ln(e^.0675t)
ln(18600)=ln(1000) + .0675t
now solve for t: t= (ln(18600)-ln(1000))/.0675
t=43.31</span>
Answer:
The answer is <u>2</u>
Step-by-step explanation:
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Answer:
<em>There's an infinite number of possible answers because there might be any multiplication of 3 for boys and any multiplication of 2 for girls. So, for example:</em>
<em>There might be 3 boys and 2 girls.</em>
<em>There might be 6 boys and 4 girls.</em>
<em>There might be 9 boys and 6 girls.</em>
<em>There might be 12 boys and 8 girls.</em>
<em>etc...</em>
<em>In each case the ratio stays the same - 3 : 2.</em>
<em>Of course there probably can't be more than a few dozens of people in one class, but theoretically we can raise the numbers up to infinite.</em>
Step-by-step explanation:<em>hope this help.</em>
Answer:
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Step-by-step explanation:
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