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dezoksy [38]
3 years ago
13

Can someone help please? ​

Mathematics
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

a

Step-by-step explanation:

it is

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The distribution of the amount of money spent by first-time gamblers at a major casino in las vegas is approximately normal in s
Lostsunrise [7]

Solution: We are given:

\mu=600, \sigma =120

We need to find the z value corresponding to probability 0.84, in order to find the how much money almost 84% of gamblers spent at casino.

Using the standard normal table, we have:

z(0.85) = 0.9945

Now we will use the z score formula to find the required amount:

z=\frac{x-\mu}{\sigma}

0.9945=\frac{x-600}{120}

0.9945 \times 120 = x - 600

119.34 = x - 600

x = 600 + 119.34        

x = 719.34

x = 720 approximately

Therefore, almost 84% of gamblers spent more than $720 amount of money at this casino.

5 0
3 years ago
Job a pays $9.95 per hour, 40 hours per week.
OLEGan [10]
Job A pays better


there are roughly 52 weeks in a year so multiply that by 40 to get the total hours worked in a year. = 2,080

2,080 hours worked per year multiplied by the hourly pay 9.95 = 20,696

Job A pays $20,696 per year

Job B only pays $17,500
4 0
3 years ago
Read 2 more answers
At the start of the month, Stephen’s savings account had a balance of $1,624. He made a $420 withdrawal each week for four weeks
goldenfox [79]
420 x 4 = 1,680. $1,624 - $1,680 = - $56. $600 x 2 = 1,200 + 1000 = 2,200. This minus the $56 he overdrew = an end of month balance of $2,144.
6 0
3 years ago
Read 2 more answers
A horse drawing is 4.5 inches in height. The actual horse is 1 inch to 1.5 feet.
Naily [24]

Answer:

6 ft 9

Step-by-step explanation:

6 0
3 years ago
Perform the indicated row operations
SVETLANKA909090 [29]

Answer:

\begin{bmatrix}2 & -1 & -4 & 7\\ 0 & -30 & 20 & -50\\ 0 & 30 & 24 & 6\end{bmatrix}

Step-by-step explanation:

Given matrix is,

\begin{bmatrix}2 & -1 & -4 & 7\\ 0 & 3 & -2 & 5\\ 0 & 10 & 8 & 2\end{bmatrix}

Operations performed,

-10R₂ → R₂

\begin{bmatrix}2 & -1 & -4 & 7\\ 0 & -30 & 20 & -50\\ 0 & 10 & 8 & 2\end{bmatrix}

3R₃ → R₃

\begin{bmatrix}2 & -1 & -4 & 7\\ 0 & -30 & 20 & -50\\ 0 & 30 & 24 & 6\end{bmatrix}

4 0
3 years ago
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