1. Recipe 1 and three
2. 0.4 to one cup
3. 0.8
Answer: 10x^2-8x+16
Step-by-step explanation:
Use the formula (b/2)^2
then plug in values:
(-8/2)^2 = -4^2 = 16
ans: 10x^2-8x+16
hope this helps
We have to solve x in terms of a, b and c:
a x - 3 b = c
a x - 3 b + 3 b = c + 3 b
a x = c + 3 b
x = ( c + 3 b ) : a
Answer:
4 ) ( c + 3 b ) / a
Yep exponential functions are shown in the answer 2
Answer:
m∠ADC = 132°
Step-by-step explanation:
From the figure attached,
By applying sine rule in ΔABD,
![\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bsin%7D%28%5Cangle%20ABD%29%7D%7B%5Ctext%7BAD%7D%7D%3D%5Cfrac%7B%5Ctext%7Bsin%7D%28%5Cangle%20ADB%29%7D%7BAB%7D)
![\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bsin%7D%28120%29%7D%7B35%7D%3D%5Cfrac%7B%5Ctext%7Bsin%7D%28%5Cangle%20ADB%29%7D%7B30%7D)
sin(∠ADB) = ![\frac{30\text{sin}(120)}{35}](https://tex.z-dn.net/?f=%5Cfrac%7B30%5Ctext%7Bsin%7D%28120%29%7D%7B35%7D)
= 0.74231
m∠ADB = ![\text{sin}^{-1}(0.74231)](https://tex.z-dn.net/?f=%5Ctext%7Bsin%7D%5E%7B-1%7D%280.74231%29)
= 47.92°
≈ 48°
m∠ADC + m∠ADB = 180° [Linear pair of angles]
m∠ADC + 48° = 180°
m∠ADC = 180° - 48°
m∠ADC = 132°