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Paladinen [302]
3 years ago
8

Jason combined 1 1/4 ounces of strawberry preserve from a jar with 7/8 of an ounce of strawberry preserve as a part of individua

l dessert bowls.
Jason plans on using 1/5 of an ounce of strawberry preserve in each dessert bowl. How many dessert bowls can he completely fill?
Mathematics
1 answer:
saul85 [17]3 years ago
4 0

Answer: 10 dessert bowls.


Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. Rewrite 1 1/4 ounces as a fraction:

(4+1)/4=\frac{5}{4}

2. You must add 5/4 ounces of strawberry preserve and 7/8 ounce of strawberry preserve, as following:

\frac{5}{4}ounces+\frac{7}{8}ounces=\frac{17}{8}ounces

3. Now you must divide the result obtained by 1/5:

\frac{17}{8}÷\frac{1}{5}=10.62

4. Therefore, you can conclude that 10 dessert bowls can be completely fill.

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Answer:

Probability =0.9898

Step-by-step explanation:

Given that, mean = 4 = 300 standard deviation = 70 n = 100 PT = H = 128 oT = 0 / V n = 70/ v 100 = 7 a) within 6 = 300 ±6 = 294, 306 P(294< ī < 306) = P[(294 - 300) 7 < (ĩ -H ï) / o ĩ < (306 300) /7)] = P(-0.86 < Z < 0.86) = P(Z < 0.86) - P(Z < -0.86) Using z table, 0.8051 - 0.1949 %3D %3D %3D = 0.6102 Probability = 0.6102 a) within 18 = 300 t 18 = 294, 318 P(294< ī < 306) = P[(282 - 300) / 7< (ã -H i) / oī< (318 - 300) /7)] = P(-2.57 < Z< 2.57) = P(Z < 2.57) - P(Z < -2.57) Using z table, =0.9949 - 0.0051 =0.9898 Probability =0.9898

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Answer:

A. (3, 8) and 2\sqrt{2}

B. (2, 4) and 2\sqrt{10}

Step-by-step explanation:

Midpoint formula: (\frac{x1+x2}{2} ,\frac{y1+y2}{2})

Distance formula: \sqrt{(x_{2}-x_{1}) ^2+(y_{2}-y_{1}) ^2 }

A. plug in the points in the formulas

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Midpoint:

(\frac{4 + 2}{2} , \frac{7+9}{2} )=6/2, 16/2 = (3,8)

Length:

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B.

(5, 5) and (-1, 3)

Midpoint:

(\frac{5-1}{2} , \frac{5+3}{2} )=4/2,8/2=(2,4)

Length:

\sqrt{(-1-5)^2+(3-5)^2} =\sqrt{-6^2+-2^2} =\sqrt{36+4} =\sqrt{40} = 2\sqrt{10}

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