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Alex Ar [27]
3 years ago
11

A car traveling at 23 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration?

Physics
1 answer:
kykrilka [37]3 years ago
8 0
We could determine the acceleration using this formula
\boxed{a= \dfrac{v_{1}-v_{0}}{t} }

Given from the question v₀ = 23 m/s, v₁ = 0 (the car stops), t = 5 s
plug in the numbers
a= \dfrac{v_{1}-v_{0}}{t}
a= \dfrac{0-23}{5}
a= \dfrac{-23}{5}
a = -4.6
The acceleration is -4.6 m/s²
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Answer:

specific heat capacity

Explanation:

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explain how you can determine if a chemical reaction a single replacement reaction or a double replacement reaction
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A wire of resistance R is cut into ten equal parts which are then connected in parallel. The equivalent resistance of the combin
Greeley [361]

Answer:

<em>The equivalent resistance of the combination is R/100</em>

Explanation:

<u>Electric Resistance</u>

The electric resistance of a wire is directly proportional to its length. If a wire of resistance R is cut into 10 equal parts, then each part has a resistance of R/10.

Parallel connection of resistances: If R1, R2, R3,...., Rn are connected in parallel, the equivalent resistance is calculated as follows:

\displaystyle \frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+...+\frac{1}{R_n}

If we have 10 wires of resistance R/10 each and connect them in parallel, the equivalent resistance is:

\displaystyle \frac{1}{R_e}=\frac{1}{R/10}+\frac{1}{R/10}+\frac{1}{R/10}...+\frac{1}{R/10}

This sum is repeated 10 times. Operating each term:

\displaystyle \frac{1}{R_e}=\frac{10}{R}+\frac{10}{R}+\frac{10}{R}+...+\frac{10}{R}

All the terms have the same denominator, thus:

\displaystyle \frac{1}{R_e}=10\frac{10}{R}=\frac{100}{R}

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R_e=R/100

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6 0
3 years ago
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Svetllana [295]

Answer:

0.702 m

Explanation:

The magnitude of the electrostatic force between two charged objects is given by Coulomb's Law:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the objects

And the force is:

- Attractive if the two charges have opposite signs (+-)

- Repulsive if the two charges have same sign (++ or --)

In this problem we have:

F=8.2\cdot 10^{-7}N is the force between the two balls

q_1 = q_2 = 6.7\cdot 10^{-9}C is the charge on each ball

Solving for r, we find the separation between the balls:

r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(9\cdot 10^9)(6.7\cdot 10^{-9})^2}{8.2\cdot 10^{-7}}}=0.702 m

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Answer:

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Explanation:

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