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Alex Ar [27]
3 years ago
11

A car traveling at 23 m/s starts to decelerate steadily. It comes to a complete stop in 5 seconds. What is its acceleration?

Physics
1 answer:
kykrilka [37]3 years ago
8 0
We could determine the acceleration using this formula
\boxed{a= \dfrac{v_{1}-v_{0}}{t} }

Given from the question v₀ = 23 m/s, v₁ = 0 (the car stops), t = 5 s
plug in the numbers
a= \dfrac{v_{1}-v_{0}}{t}
a= \dfrac{0-23}{5}
a= \dfrac{-23}{5}
a = -4.6
The acceleration is -4.6 m/s²
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a = F/m

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t = time for which the force is applied = 5 sec

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using the equation

v = v₀ + a t

inserting the values

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v = 14.7 m/s

consider the motion of cart after it flies off the cliff in vertical direction :

v' = initial velocity in vertical direction = 0 m/s

a' = acceleration in vertical direction = g = acceleration due to gravity = 9.8 m/s²

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using the kinematics equation

Y' = v' t' + (0.5) a' t'²

100 = (0) t' + (0.5) (9.8) t'²

t' = 4.52 sec


consider the motion of cart along the horizontal direction after it flies off the cliff

X = distance traveled from the base of cliff = ?

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distance traveled from the base of cliff is given as

X = v t'

X = 14.7 x 4.52

X  = 66.4 m


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