I know that the answer is 3 because 1+2 is 3
Answer:
0.15694 m
Explanation:
m = Mass of block = 
v = Velocity of block = 11.2 m/s
k = Spring constant = 110 N/m
Here the kinetic energy of the fall and spring are conserved

The amplitude of the resulting simple harmonic motion is 0.15694 m
t = 0.527 s
<u>It accelerates for 0.527 s.</u>
<u>Explanation:</u>
We use the formula:
v = u+at
Given:
v = 106 m/s
u = 0 (since no gravity)

So applying the formula,
v = u+at
106 = 0 + 201t
t = 106/201
t = 0.527 s
Answer:
3.86×10⁶ Newton/coulombs
Explaination:
Applying,
E = F/q....................... Equation 1
Where E = Electric Field, F = Force, q = charge.
From the question,
Given: F = 5.4×10⁻¹ N, q = -1.4×10⁻⁷ coulombs
Substitute these values into equation 1
E = 5.4×10⁻¹/ -1.4×10⁻⁷
E = -3.86×10⁶ Newtons/coulombs
Hence the magnitude of the electric field created by the
negative test charge is 3.86×10⁶ Newton/coulombs