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nordsb [41]
3 years ago
11

Felix expends 100 W of power to clomb 10 meters in 20 seconds how much force does he exert

Physics
2 answers:
saw5 [17]3 years ago
7 0

Answer:

200 N

Explanation:

yulyashka [42]3 years ago
3 0

Answer:

200 N

Explanation:

Power = work / time

Work = force × distance

Therefore:

Power = force × distance / time

100 W = F × 10 m / 20 s

F = 200 N

He exerted 200 N.

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Ilya [14]

Answer:D increase in frequency

Explanation:

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A ___________ is how strong the push or pull is
KatRina [158]
The answer is force
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while test flying the new f-22 raptor fighter jet, test pilot bob put the plane in a horizontal loop while flying at the speed o
sveticcg [70]

Given

v = 343 m/s

ac = 5g

ac = 5*9.8 m/s^2

ac = 49 m/s^2

where,

v: velocity

ac = centripetal aceleration

Procedure

We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration ac; centripetal means “toward the center” or “center seeking”.

Formula

\begin{gathered} a_c=\frac{v^2}{r} \\ r=\frac{v^2}{a_c} \\ r=\frac{(343m/s)^2}{49m/s^2} \\ r=2401\text{ m} \end{gathered}

The minimum radius not to exceed the centripetal acceleration is 2401 m.

8 0
1 year ago
How much power is used by a car engine if it does 48496 J of work in 4 min?
elena-14-01-66 [18.8K]

<em>Hope this will help u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>✌</em><em>✌</em><em>✌</em>

8 0
3 years ago
Read 2 more answers
A wooden artifact from a Chinese temple has a 14C activity of 41.0 counts per minute as compared with an activity of 58.2 counts
prohojiy [21]

Answer:

Explanation:

The relation between activity and number of radioactive atom in the sample is as follows

dN / dt = λ N where λ is disintegration constant and N is number of radioactive atoms

For the beginning period

dN₀ / dt = λ N₀

58.2 = λ N₀

similarly

41 = λ N

dividing

58.2 / 41 = N₀ / N

N = N₀ x .70446

formula of radioactive decay

N=N_0e^{-\lambda t }

.70446 =e^{-\lambda t }

- λ t = ln .70446 =   - .35

t = .35 / λ

λ = .693 / half life

= .693 / 5715

= .00012126

t = .35 / .00012126

= 2886.36

= 2900 years ( rounding it in two significant figures )

7 0
3 years ago
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