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3 years ago

What is the drawback to using superconductors?

Physics

1 answer:

Fittoniya [83]3 years ago

7 0

Answer:

Option A

The cost of keeping the semiconductor below the critical temperature is unreasonable

Explanation:

First of all, we need to understand what superconductors are. Superconductors are special materials that conduct electrical current with almost zero resistance. This means that there is little or no need for a voltage source to be connected to them. As a matter of fact, once a superconductor is connected to a power supply, one can remove the power supply and the current will still flow.

However, most superconducts can only conduct at very low temperatures up to -200 degrees Celcius. This is because, at that temperature, their atoms and molecules are relatively settled, hence they pose little or no resistance to the flow of current.

This as you can guess is extremely difficult to do, as you will need a lot of effort to cool it to that temperature and maintain it.

This makes option a the answer:

The cost of keeping the semiconductor below the critical temperature is unreasonable.

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Pls help A ball rolls horizontally off a 100-meter-tall cliff at 40 meters per second. How far does the ball travel horizontally

svet-max [94.6K]

First find the time it takes for the ball to reach the ground using the vertical component of its position vector:

$y=y_0+v_{0y}t+\dfrac12a_yt^2$

$\implies0=100\,\mathrm m+\dfrac12\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2$

$\implies t=4.52\,\mathrm s$

Meanwhile, the horizontal component of the ball's position vector is

$x=x_0+v_{0x}t+\dfrac12a_xt^2$

$\implies x=\left(40\,\dfrac{\mathrm m}{\mathrm s}\right)t$

After about 4.52 s, the ball has traveled a horizontal distance of

$x=\left(40\,\dfrac{\mathrm m}{\mathrm s}\right)(4.52\,\mathrm s)=180.8\,\mathrm m$

which you would round to 200 m, so the answer is B.

8 0

3 years ago

An infinite sheet of charge is located in the y-z plane at x = 0 and has uniform charge denisity σ1 = 0.51 μC/m2. Another infini

NNADVOKAT [17]

Answer:

E_total = 5.8 10⁴ N /C

Explanation:

In this problem they ask to find the electric field at two points, the electric field is a vector magnitude, so we can find the field for each charged shoah and add them vectorally at the point of interest.

To find the electric field of a charged conductive sheet, we can use the Gauss law,

Ф = E. d S = $q_{int}$ / ε₀

Let us use as a Gaussian surface a small cylinder, with the base parallel to the sheet, the electric field between the sheet and the normal one next to the cylinder has 90º, so its scalar product is zero, the electric field between the sheet and the base has An Angle of 0º, therefore the scalar product is reduced to the algebraic product.

Let's look for the electric field for plate 1

The total flow is the same for each face, as there are two sides of the cylinder

2E A = q_{int} /ε₀

For the internal load we use the concept of surface density

σ = q_{int1} / A

q_{int1} = σ₁ A

Let's replace

2E A = σ₁ A /ε₀

E₁ = σ₁ / 2ε₀

For the other plate we have a field with a similar expression, but of negative sign

E₂ = -σ₂ / 2ε₀

The total field is,

E_total = σ₁ / 2ε₀ + σ₂ / 2ε₀

E_total = (σ₁ + σ₂) / 2ε₀

Let us apply this expression to our case, when placing a sheet without electric charge, a charge is induced for each sheet, the plate 1 that has a positive charge the electric field is protruding to the right and the plate 2 that has a negative charge creates a incoming field, to the right, as the two fields have the same address add

The conductive sheet in the middle pate undergoes an induced load that is created by the other two plates, but because the conductive plate the charges are mobile and are replaced.

E_total = (0.51 +0.52) 10⁻⁶ / 2 8.85 10⁻¹²

E_total = 5.8 10⁴ N /C

Note that the field is independent of the distance between the plates

4 0

3 years ago

A volumetric flask made of Pyrex is calibrated at 20.0°C. It is filled to the 150-mL mark with 34.5°C acetone. After the flask i

8_murik_8 [283]

Answer:149.73 ml

Explanation:

Given

$\beta \ of\ acetone=1.50\times 10^{-4} ^{\circ}C^{-1}$