Answer:
The answer is QR,RS, and ST
Step-by-step explanation:
i hope this helps .
Answer:
The year in which the population passed 6 billion is 2000.
Step-by-step explanation:
We are given that a student looking at global population figures remarks that between the years 1950 and 2010 the global population can be modeled by the equation 300y = 23t − 44180; where (1950 ≤ t ≤ 2010).
And we have to calculate the year in which the population passed 6 billion.
The given expression is;
Firstly, put t = 1960 {as t lies between 1950 and 2010}
= 3 billion
But we have to cross the population by 6 billion.
Now, put t = 1999 in the expression;
= 5.99 billion
Still, it's not passed 6 billion, so finally put t = 2000;
= 6.1 billion
Now, the global population has crossed 6 billion.
Hence, the year in which the population passed 6 billion is 2000.
Answer:
-3
Step-by-step explanation:
Simplify the following:
(-9 (-5) - 9)/(-12)
-9 (-5) = 45:
(45 - 9)/(-12)
| 3 | 15
| 4 | 5
- | | 9
| 3 | 6:
36/(-12)
The gcd of 36 and -12 is 12, so 36/(-12) = (12×3)/(12 (-1)) = 12/12×3/(-1) = 3/(-1):
3/(-1)
Multiply numerator and denominator of 3/(-1) by -1:
Answer: -3
The value of is -80
<h3><u>Solution:</u></h3>
Given that x y is a real number
Also given that
We are asked to find the value of
To solve it we have to first solve terms in brackets.