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bazaltina [42]
2 years ago
5

During a building project, a brick is

Mathematics
1 answer:
taurus [48]2 years ago
3 0

The brick will fall to the ground after 9 secs.

<h3>What are quadratic equations?</h3>

Given the equation for height as a function of time is  h(t) = -16t2 + 1,296

The height of the brick on the ground is h(t) = 0. Substitute h(t) = 0 into the equation as shown:

  • -16t2 + 1,296 = 0

Subtract 1296 from both sides

-16t² + 1,296 - 1296 = 0 - 1296

16t² = 1296

t² = 1296/16

t² = 81

t = 9secs

Hence the brick will fall to the ground after 9 secs.

Learn more on equations here: brainly.com/question/13763238

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A 9.85 m ladder is placed against a wall. The height to the top of the ladder is 5 m more than the distance between the wall and
Dafna1 [17]

Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.​

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

Hypotenuse^2=Base^2+Perpendicular^2

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

Using the Pythagoras theorem, we get

(9.85)^2=x^2+(x+5)^2

97.0225=x^2+x^2+10x+25

0=2x^2+10x+25-97.0225

0=2x^2+10x-72.0225

Here, a=2, b=10,c=-72.0225. Using the quadratic formula, we get

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\dfrac{-10\pm \sqrt{(10)^2-4(2)(-72.0225)}}{2(2)}

x=\dfrac{-10\pm \sqrt{676.18}}{4}

Approximating the value, we get

x=\dfrac{-10\pm 26}{4}

x=\dfrac{-10+26}{4},\dfrac{-10-26}{4}

x=\dfrac{16}{4},\dfrac{-36}{4}

x=4,-9

Distance cannot be negative so x\neq -9.

Now we have x=4

x+5=4+5

x+5=9

Therefore, the base is 4 m and the height is 9 m.

5 0
3 years ago
Help help plz help plz i will put u breanliest
Marina86 [1]

Answer:

Step-by-step explanation:

96

5 0
2 years ago
What are the first three terms of the sequence defined by the recursive function an=an-1-(an-2-4), when a5=-2 and a6=0
BaLLatris [955]

Answer:

6, 10, 8

Step-by-step explanation:

aₙ= aₙ₋₁ - (aₙ₋₂ - 4)= aₙ₋₁ - aₙ₋₂ + 4

a₅= -2

a₆= 0

-----------

aₙ₋₂= aₙ₋₁ - aₙ + 4

  • a₄= a₅- a₆ + 4 = -2 - 0 + 4 = 2
  • a₃= a₄ - a₅ + 4 = 2 - (-2) + 4 = 8
  • a₂= a₃ - a₄ + 4 = 8 - 2 + 4 = 10
  • a₁= a₂ - a₃ + 4 = 10 - 8 + 4 = 6

The first 3 terms: 6, 10 and 8

4 0
2 years ago
Find the quotient. 8,489÷9
eimsori [14]
The answer is 943.2.
4 0
2 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME ASAP PLEASEEEE!!!​
Rom4ik [11]

Answer:

11.4

Step-by-step explanation:

So we know that Triangle ACB is similar to Triangle EFD.

This means that their sides are proportional to each other.

We want to find x or side AB. To do so, we can set up a proportion.

The proportional side to AB is ED. Let's also use BC since we know its value. The proportional side to BC is DF. Thus:

\frac{AB}{ED}=\frac{BC}{DF}

Substitute x for AB, 3.8 for Ed, 15 for BC, and 5 for DF. Thus:

\frac{x}{3.8}=\frac{15}{5}

Reduce the right:

\frac{x}{3.8}=\frac{3}{1}

Cross multiply:

x=11.4

So, the value of x is 11.4

And we're done!

7 0
3 years ago
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