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Anarel [89]
3 years ago
6

Please explain by showing your work.

Mathematics
1 answer:
Levart [38]3 years ago
3 0

Answer:

x=1.8

Step-by-step explanation:

To solve this equation, we can use PEMDAS and the various properties.

First, use the distributive property on all parenthesis, since parenthesis come first.

4x-1+6x+6x+24=52

Now we can use the commutative property to add all like terms.

16x+23=52

Now just subtract on both sides.

52-23=29 so our equation is 16x=29

To isolate x, divide both sides by 16.

x=1.8 rounded up

Hope this helps!

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Nimfa-mama [501]

The given expression is :

2xx+3-5(x-2)

We know that, x{\cdot}x=x^2

=2x^2+3-5(x-2)\\\\=2x^2+3+(-5)(x)+(-5)(-2)\\\\=2x^2+3-5x+10

Aleena expands 2xx+3-5(x-2) as 2x²+3-5x-10. She is mistaken because the sign before 10 should be +10 instead of -10. Hence, the correct expanded form is 2x²+3-5x+10. Hence, this is the required solution.

5 0
3 years ago
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Lera25 [3.4K]

Answer:

Step-by-step explanation:

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3 years ago
what percent of the students who spend less than 4 hours a week on screens reported a grade average above 80? round your answer
kifflom [539]

Answer:

okay so 400%

Step-by-step explanation: Here's why so basically 80 divided by 4 is 20 and 20 rounded to the nearest tenth is 4 so 4 turned into a percentage is 400%. Sorry if I am incorrect.

8 0
2 years ago
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KIM [24]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
A liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle. Calculate the concentration
MrMuchimi

Answer:

20 mg/ml.

Step-by-step explanation:

We have been given that a liquid oral concentrate of morphine sulfate contains 2.4 g of morphine sulfate in a 120-mL bottle.

\text{Concentration of morphine sulfate on g/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}

To convert the concentration of morphine sulfate on a mg/mL basis, we need to convert 2.4 grams to milligrams.

1 gram equals 1000 milligrams.

\text{Concentration of morphine sulfate on mg/mL basis}=\frac{\text{2.4 g}}{\text{120 ml}}\times\frac{\text{1,000 mg}}{\text{1 g}}

\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2.4\times\text{1,000 mg}}{\text{120 ml}}

\text{Concentration of morphine sulfate on mg/mL basis}=\frac{2400\text{ mg}}{\text{120 ml}}

\text{Concentration of morphine sulfate on mg/mL basis}=\frac{20\text{ mg}}{\text{ml}}

Therefore, the concentration of morphine sulfate would be 20 mg per ml.

5 0
3 years ago
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