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valina [46]
2 years ago
5

Find the least common multiple (LCM) of 7, 10, and 20.

Mathematics
2 answers:
Aleonysh [2.5K]2 years ago
7 0

Answer:

140

Step-by-step explanation:

140 is the first multiple that all 3 numbers share.

sveticcg [70]2 years ago
5 0
140


When finding the multiples of 7,10, and 20, the first number you see they all have in common besides 1, is 140
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Find f(0) and f(2) for the given exponential function. f(x) = (1/2)^-x
Aliun [14]
For 0 it will equal 1 because anything to the 0th power is 1 except 0 to the 0.

For 2, It will equal for because when you raise a fraction to the negative power you flip it and that gets rid of the negative number so then you will have 2 to the second and you will get 4.

f (0) = 1, f (2) = 4
8 0
3 years ago
Identify the variable(s) in the expression below.<br> 5 + 12w
tatiyna

Answer:

w is the variable

Step-by-step explanation:

the letters you see next to the numbers the variable.

8 0
2 years ago
A tennis player wins a match 55% of the time when she serves first and 47% of the time when her opponent serves first. The playe
Ray Of Light [21]

ok so she has a 50% chance of serving first so if she serves first she has a 55% percent chance of winning multiply .55 and .50 to get .275 now she also has a 50% chance of not serving first so multiply .47 and .50 to get .235 now that you have the two probabilities of her winning you add them together so .275+.235 = .51 so she has a <u>51%</u> chance of winning the game
8 0
3 years ago
Look at the attachment pls!!
Naddika [18.5K]

The terms -12x^2y and 4x^2y can be added to 3x^2y to result in a monomial.

Step-by-step explanation:

Given term is;

3x^2y

A monomial is an algebraic expression that consists of only one term.

So in the given expressions, we will add the terms which have same variables as given terms.

Given options are;

3xy\\-12x^2y\\2x^2y^2\\7xy^2\\-10x^2\\4x^2y\\3x^3

The terms -12x^2y and 4x^2y can be added to 3x^2y to result in a monomial.

4 0
3 years ago
The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t
damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that \mu = 3

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498

P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494

P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240

P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240

Then

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0
3 years ago
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