I think the answer is a. because all sides are the same.
1 side = 38
side m = probably 38
Hope this helped☺☺
Explanation:
Here are the few points that might help you to avoid procrastination.
1. Keep your workstation clean, that does not make you feel overburdened with work.
2. Break down your work into pieces.
3. Make short term tasks rather long terms.
4. Prioritize goals with a deadline.
5. More you delay more you will be working under pressure so better not to delay.
6. Some times talk to yourself, tell yourself the more you delay worse it will get for you only.
These points should help.
Answer:
Step-by-step explanation:
Mark is on a quiz bowl team. He answers his quiz bowl questions correctly one-third of the time. Which is a way you could simulate the probable outcomes of this event with a six-sided number cube?
A.correct: a roll of 6 incorrect a roll that is not 6
B.correct: a roll of an even number incorrect a roll of an odd number
C.correct: a roll of a number less than 3 incorrect: a roll of a greater than or equal to 3
D. correct: a roll of a number that is not divisible by 3 incorrect a roll of a number that is divisible by 3
\
Answer
2.0/5
5
6.6M people helped
The probability being fixed at 1/3, let's find which event in rolling a 6 sided dye will generate a probability of 1/3.
A- 6 sided number cube: with one roll (INCORRECT), however with a 3 sided number cube, P(0ne roll) = 1/3 (CORRECT)
B- A roll of an even number : P(even number) =3/6 =1/2 (INCORRECT), and a roll of an odd number P(odd number) = 3/6 = 1/2 (INCORRECT)
C- A roll of a number less than 3 , P(less than 3) =2/6 =1/3 CORRECT), whereas :a roll greater than or equal to 3. INCORRECT
D. A roll of a number that is not divisible by 3, P(not divisible by 3) = 4/6 =2/3 (INCORRECT): P( number number that is divisible by 3) =2/6 1/3 CORRECT
Answer:
- 0 ≤ h
- The only asymptote in the domain is the horizontal asymptote c = 0.
- The only intercept in the domain is (x, y) = (0, 0).
- Maximum concentration occurs at h ≈ 1.95.
- About 1:33 pm
Step-by-step explanation:
1. For functions involving time, it usually makes no sense to evaluate them for negative values of time. At some point in the future, the value of the function is sufficiently small as to be "don't care", so that value of time is a good upper limit on the domain. Here, that might be about 100 hours, where the concentration is about 0.02%.
A reasonable domain might be 0 ≤ h ≤ 100.
__
2. In the domain, the only asymptote is horizontal. As h gets large, the value of the function becomes 2/h, so approaches zero.
The horizontal asymptote is C=0.
__
3. The only intercept is the origin, where C(0) = 0.
__
4. A graph shows the function maximum occurs at about h = 1.95.
__
5. A graph shows the value of C(5.544) ≈ 0.5. If we assume that C(h) represents the concentration in %, then the next injection should be given about 5.544 hours after 8 am, or at 1:33 pm. (My calculator converts hours to hours:minutes, so there is no "work" to show.)
