Answer:
thermodynamically unstable but kinetically stable.
Explanation:
The complete question is as follows:
Under physiological conditions, peptide bond formation and degradation both require enzymes, but only formation requires coupling to GTP hydrolysis. Based on this information, peptide bonds under physiological conditions are:
A. both thermodynamically and kinetically stable.
B.thermodynamically unstable but kinetically stable.
C.thermodynamically stable but kinetically unstable.
D. both thermodynamically and kinetically unstable.
- The term thermodynamically unstable refers to the fact that the peptide bonds are prone to breakage under physiological conditions.
- The reason why one can conclude the thermodynamic instability of the peptide bonds under physiological condition is that there is a need for a source of energy i.e. GTP hydrolysis for the formation of the peptide bond.
- The fact that the breakage of peptide does not require any input of energy but the only formation does confirms the fact that under physiological conditions they are thermodynamically unstable.
- Even though they are thermodynamically unstable, they are kinetically stable because both the formation and degradation require enzymes.
- The function of enzymes is to decrease the activation energy and hence, increase the rate of reaction. This means that if the enzymes are absent the rate of breakage of peptide bonds would be really slow this points out to the fact that they are kinetically stable under physiological conditions.
Answer:
Urea is produced when foods containing protein, such as meat, poultry, and certain vegetables, are broken down in the body. Urea is carried in the bloodstream to the kidneys, where it is removed along with water and other wastes in the form of urine.
Explanation:
Answer:
Abiotic factors can all be measured to show the living conditions in an ecosystem.
Light meters can be used to measure light intensity. ...
Errors can be made when measuring light intensity by accidentally shading the light meter. ...
Soil moisture and soil pH meters are also available.
Explanation:
Answer:
anwser is C
Explanation:
they both have 6 carbon atoms so A is wrong
both are monosacchride so B is wrong
both have same molecular formula which is (C₆H₁₂O₆) so D is wrong
in glucose the anomeric carbon is the first carbon, whereas in fructose, the anomeric carbon is the second carbon. The anomeric carbon is the one containing the carbonyl group (carbonyl group is a functional group composed of a carbon atom double-bonded to an oxygen atom: C=O)
