Question

The average intensity of light emerging from a polarizing sheet is 0.689 W/m2, and that of the horizontally polarized light incident on the sheet is 0.930 W/m2. Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

Answer 1

Answer:

$\theta=30.60^0$

Explanation:

given,                                                      

intensity of light(S) = 0.689 W/m²        

intensity of (S_0) =  0.930 W/m²          

angle of transmission axis = ?            

using Malus law                                

$s = s_0 cos^2\theta$        

$cos^2\theta= \dfrac{s}{s_0}$          

$cos\theta= \sqrt{\dfrac{s}{s_0}}$          

$\theta=cos^{-1}(\sqrt{\dfrac{s}{s_0}})$            

$\theta=cos^{-1}(\sqrt{\dfrac{0.689}{0.930}})$

$\theta=cos^{-1}(\sqrt{0.7408})$                        

$\theta=cos^{-1}({0.86073})$                  

$\theta=30.60^0$