<h2>
Answer:</h2>
1.77V
<h2>
Explanation:</h2>
The electromotive force voltage (E) in a cell, is related to the lost voltage (
) and the terminal voltage (
) as follows;
E = -
Where;
The lost voltage () is the product of the internal resistance (r) of the cell and current (I) in the cell. i.e
= I x r
<em>Substitute </em><em> = I x r into equation (i) as follows;</em>
E = - (I x r) ----------------------(ii)
<em>According to the question;</em>
E = 1.54V
I = 2.15A
r = 0.105Ω
<em>Substitute these values into equation(ii) as follows;</em>
1.54 = - (2.15 x 0.105)
1.54 = - (0.22575)
1.54 = - 0.22575
<em>Solve for </em><em>;</em>
= 1.54 + 0.22575
= 1.54 + 0.22575
= 1.77V
Therefore, the terminal voltage of the cell is 1.77V
Answer:
1768 N
Explanation:
We can solve the problem by using Newton's second law:
where
F is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, we have a car of mass
m = 884 kg
And its acceleration is
Substituting into the equation, we find the net force on the car:
Momentum
mava + mbvb = mava '+ mbvb'
(300 x 10)+(150 x 0) = (300 x 4.12)+(150 x vb')
3000=1236+150vb'
1764 = 150vb'
vb'=+11.76 m/s ≈ +11.8 m/s (positive sign, to the right)
Answer:
heya answer option b
Explanation:
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